M = 90 kg,
On Mars: g = 3.71 m/s²
Weight = m · g = 90 kg · 3.71 m/s² = 333.9 N
1 N = 0.2248 lbf
333.9 · 0.2248 = 75.06072 lbf ≈ 75 lbf
$260
I don’t know what model/formula you are supposed to be using.
But what I did first was calculated what 30% of 2700$ is.
2700 x .3 = 810
So it depreciates $810 per year.
$810 x. 3 years = 2430
2700 - 2430 = 260
In three years, the laptop will be worth $260
The lengths of the line segments are summarized in the following list:
- DF = 3
- DE = 8 / 3
- FG = 3
- FH = 9 / 2
- GH = 3 / 2
- EH = - 11 / 6
<h3>How to calculate the length of a line segment based on point set on a number line</h3>
Herein we have a number line with five points whose locations are known. The length of each line segment is equal to the arithmetical difference of the coordinates of the rightmost point and the leftmost point:
DF = - 1 - (- 4)
DF = 3
DE = (- 1 - 1 / 3) - (- 4)
DE = 3 - 1 / 3
DE = 8 / 3
FG = 2 - (- 1)
FG = 3
FH = (3 + 1 / 2) - (- 1)
FH = 4 + 1 / 2
FH = 9 / 2
GH = (3 + 1 / 2) - 2
GH = 1 + 1 / 2
GH = 3 / 2
EH = (3 + 1 / 2) + (- 1 - 1 / 3)
EH = - 2 + (1 / 2 - 1 / 3)
EH = - 2 + 1 / 6
EH = - 11 / 6
To learn more on lengths: brainly.com/question/8552546
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Answer: Alvin = 42 yrs , Elga = 21 yrs
Step-by-step explanation:
Let Elga's age be x , and Alvin's age be y ,since Alvin is two times Elga's age , then
Alvin's age = 2x , that is
y = 2x ............... equation 1
The sum of their ages is 63 implies
x + y = 63 .............. equation 2
Solving the resulting linear equations by substitution method.
Substitute equation 1 into equation 2 , we have
x + 2x = 63
3x = 63
x = 63/3
x = 21
Therefore : Elga is 21 years old , then Alvin will be 21 x 2, which will be 42
Answer:
the student should score atleast 229 to be among the top 10%.
Step-by-step explanation:
in terms of the normal distribution, and if the table that you're using calculates the area of the normal distribution from the mean to a point x, only then what we are actually finding the value 'x' at which the z-score is at 40% (the rest 50% is already skipped by the table)
after finding the the value at this z-score, we can find the value of x at which the score is in the top 10% range.
we can find the z-score either using a normal distribution table or calculator. (but be sure what area is it calculating)
looking at the table the closest value we can find is, 0.4015 at z = 1.29 ((it is above 40% because we want to be in the top 10% range)
the student should score atleast 229 to be among the top 10%.
