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alekssr [168]
3 years ago
14

Find four consecutive even integers such that the sum of the second and fourth and integer is one half times the sum of the firs

t and third integers
Mathematics
1 answer:
Artyom0805 [142]3 years ago
8 0
Okay lets create an eqn from that information

A first int, B second int, C third int, D fourth int.

B = A + 2
C = A + 4
D = A + 6
A is the smallest integer

B + D = 0.5 (A + C) 

Now lets substitute

(A + 2) + (A + 6) = 0.5(A + (A + 4))
now lets dist

2a + 8 = 0.5(2a +4)
2a + 8 = a + 2
a + 8 = 2
a = -6

B = -6 +2
B = -4
C = -6 + 4
C = -2
D = -6 + 6
D = 0

Now using B + D = 0.5(A + C)
-4 + 0 = 0.5(-6 + (-2))
-4 = 0.5 (-8)
-4 = -4

Correct 
Therefore, First integer is -6, second integer is -4, third integer is -2 and fourth integer is 0
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grigory [225]

Answer:

2.25 or 2 1/4

Step-by-step explanation:

Easy. you add them like regular numbers. 1/4 + 2 = 0.25 + 2 =2.25 and/or 2 1/4

8 0
2 years ago
What is the value of x in the equation below?
zubka84 [21]
First you multiply 6(x) then you multiple 6(8)

Your equation should now look like this: 6x-48=72

Subtract 48 from both sides

Your equation should now look like 6x=120

Divide by 6

Answer is 20
7 0
2 years ago
Pyramid A is a right square pyramid with a height of 100 m and a square base with a perimeter of 356 m. Pyramid B has a square b
Tomtit [17]

Answer:

The volume of pyramid B is 3.5 times greater than the volume of pyramid A

Step-by-step explanation:

The area of squared based a pyramid is given by:

Area = \frac{1}{3}*s*s*h

Where 's' the length of the side of the base and 'h' is the height.

For pyramid A:

h= 100 m

s= 356/4 = 89 m

Area_A = \frac{1}{3}*89*89*100\\Area_A=264,033.33\ m^3

For pyramid B:

h= 215 m

s= 456/4 = 114 m

Area_B = \frac{1}{3}*114*114*215\\Area_B=931,380\ m^3

Pyramid B has a greater volume and the ratio between volumes is:

\frac{Area_B}{Area_A} =\frac{931,380}{264,033.33}\\\frac{Area_B}{Area_A} =3.5

3 0
3 years ago
What are the solutions to 4(x+5)^2=4?
aleksandr82 [10.1K]
(X+5)²=4/4
X+5=1,          X+5=-1
X=1-5            X=-1-5
X=-4             X=-6
                      
4 0
3 years ago
Read 2 more answers
What is the surface area of the cylinder with height 4 mi and radius 3 mi? Round your answer to the nearest thousandth.
Norma-Jean [14]

Answer:

The surface area of the cylinder will be "131.88".

Step-by-step explanation:

The given values are:

Height of cylinder,

h = 4 m

Radius of cylinder,

r = 3 m

As we know,

The surface are of cylinder is:

⇒  A_s=2 \pi r(h+r)

On substituting the values, we get

⇒       =2\times 3.14\times 3(4+3)

⇒       =18.84\times 7

⇒       =131.88

5 0
2 years ago
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