The angle between two vectors is given by:
cos (x) = (v1.v2) / (lv1l * lv2l)
We have then:
v1.v2 = (2, -5). (4, -3)
v1.v2 = (2 * 4) + (-5 * (- 3))
v1.v2 = 8 + 15
v1.v2 = 23
We look for the vector module:
lv1l = root ((2) ^ 2 + (-5) ^ 2)
lv1l = 5.385164807
lv2l = root ((4) ^ 2 + (-3) ^ 2)
lv2l = 5
Substituting values:
cos (x) = (23) / ((5.385164807) * (5))
x = acos ((23) / ((5.385164807) * (5)))
x = 31.33 degrees
Answer:
The angle between the two vectors is:
x = 31.33 degrees
If I understand what you are asking, you can use the median as an average since it is not affected by the mean ( median is a measure of center). Since a mean is affected by outliers, it might lower the score if there are very low outliers. But note that if there are outliers way <em>greater </em>it can increase the average. You can use the Inter Quartile Range if shown on a box plot ( measure of variability).
Answer:
option (a) f(x)= 1/x+2
Step-by-step explanation:
(a) f(x) = 1/ x+2
To find the restriction for domain , we set the denominator =0 and solve for x
x+2 =0, so x=-2
When x=-2 then denominator becomes 0 that is undefined.
So, domain is all real numbers except -2
(b) f(x)= 2x
In this function, there is no denominator or square root or log function
so there is no restriction for x, hence domain is all real numbers
(c) f(x) = 2x-2
In this function, there is no denominator or square root or log function
so there is no restriction for x, hence domain is all real numbers
f(x) = 1/ sqrt(x+2)
if we have square root in the denominator then we set the denominator >0 and solve for x. because square root of negative values are undefined
x+2>0, x>-2
Hence domain is all real numbers that are greater than -2
Answer:
21
Step-by-step explanation:
Idk
