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4 years ago

What generates the magnetic field in a current carrying wire?

1 answer:

5 0

The electricity causes the magnetic field. the electricity changes the magnetic waves around the wire causing the wires waves to change, creating an electro magnet

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A circular loop of flexible iron wire has an initial circumference of 165.0cm, but its circumference is decreasing at a constant

djverab [1.8K]

Answer:

0.005 V

Explanation:

We are given that

Initial circumference of circular loop=C=165 cm

Rate of circumference, $\frac{dC}{dt}=12 cm/s$

Magnetic field,B=0.5 T

We have to find the induced emf at time t=9 s

We know that induced amf,E= $\frac{Bd(A)}{dt}$

Area of circular coil,A= $\pi r^2$

$E=B\frac{d(\pi r^2)}{dt}=B(2\pi r)\frac{dr}{dt}$

Circumference of circular coil,C= $2\pi r$

$165=2\pi r$

$r=\frac{165}{2\pi}$

$\frac{dr}{dt}=\frac{1}{2\pi}\frac{dC}{dt}=\frac{1}{2\pi}\times (12)=\frac{6}{\pi} cm/s=\frac{6\times 10^{-2}}{\pi} m/s$

Radius of coil at time t=9 s

$r=\frac{165}{2\pi}-(\frac{6}{\pi}\times 9)=9.08 cm=9.08\times 10^{-2} m$

$1 m=100 cm$

E= $-0.5(2\pi\times 9.08\times 10^{-2})\times \frac{6\times 10^{-2}}{\pi}=-0.005 V$

Magnitude of induced emf=0.005 V

4 0

3 years ago

Read 2 more answers

A 0.017-kg acorn falls from a position in an oak tree that is 18.5 meters above the ground.

Genrish500 [490]

Answer:

Velocity= 19.05 m/s

Kinetic energy= 3.08 J

Explanation:

The corn possess potential energy. Feom law of conservation of energy, all the potential eneegy will be converted to kinetic energy, with negligible friction.

Potential energy, PE= kinetic energy, KE

Potential energy is given by mgh while kinetic energy is given by $0.5mv^{2}$

Equating

$mgh=0.5mv^{2}$

Making v the subject of the formula then

$v=\sqrt {2gh}$

Substituting 9.81 m/s2 for g and 18.5 m for h then the velocity will be

$v=\sqrt {2\times 9.81\times 18.5}=19.0517715711689\ m/s\\v\approx 19.05\ m/s$

To get the kinetic eneegy, since PE=KE AND KE is

$KE=0.5mv^{2}$

Substituting v with 19.05 and m with 0.017 kg we have

$0.5\times 0.017\times 19.05^{2}=3.08467125/ J\approx 3.08 J$

This can also be achieved by mgh since PE=KE hence 0.17*9.81*18.5=3.085245 J and the results are slightly different due to small energy losses and rounding off of values.

7 0

3 years ago

A planet has two small satellites in circular orbits around the planet. the first satellite has a period 18.0 hours and an orbit

puteri [66]

The two satellites orbit around the same planet, so we can use Kepler's third law, which states that the ratio between the cube of the radius of the orbit and the orbital period is constant for the two satellites:
$\frac{r_1^3}{T_1^2}= \frac{r_2^3}{T_2^2}$
where
$r_1$ is the orbital radius of the first satellite
$r_2$ is the orbital radius of the second satellite
$T_1$ is the orbital period of the first satellite
$T_2$ is the orbital period of the second satellite

If we use the data of the problem and we re-arrange the equation, we can calculate the orbital period of the second satellite:
$T_2 = \sqrt{T_1^2 ( \frac{r_2}{r_1} )^3} = \sqrt{(18.0 h)^2 ( \frac{3\cdot 10^7 m}{2 \cdot 10^7 m} )^3} = 33.1 h$

8 0

3 years ago

On the coast of Georgia, warm air usually picks up water vapor over the Atlantic Ocean. What will happen when the warm, moist ai

strojnjashka [21]

Answer:

C. The warm air will rise, causing water vapor to condense and form clouds.

Explanation:

8 0

4 years ago

A ball of 0.5kg slows down from 5m/s to 3m/s. Calculate the work done in the process

ivann1987 [24]

Answer: Cannot determine cause we need to know the change of time to calculate the work.

Explanation:

m = 0.5kg

V = 3m/s - 5m/s = -2m/s

P = W/t = Fv

F = ma

W = Fvt

W = (0.5)(9.8)t = 4.9t

4 0

2 years ago