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Paha777 [63]
2 years ago
5

A ball of 0.5kg slows down from 5m/s to 3m/s. Calculate the work done in the process

Physics
1 answer:
ivann1987 [24]2 years ago
4 0
Answer: Cannot determine cause we need to know the change of time to calculate the work.

Explanation:

m = 0.5kg

V = 3m/s - 5m/s = -2m/s

P = W/t = Fv

F = ma

W = Fvt

W = (0.5)(9.8)t = 4.9t



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Suppose an asteroid orbiting the sun had an orbital period of 7. 5 years. What would its orbital radius be?.
creativ13 [48]

By using the orbital period equation we will find that the orbital radius is r = 4.29*10^11 m

<h3>What is the orbital period?</h3>

This would be the time that a given body does a complete revolution in its orbit.

It can be written as:

T = \sqrt{\frac{4*\pi ^2*r^3}{G*M} }

Where:

  • π = 3.14
  • G is the gravitational constant = 6.67*10^(-11) m^3/(kg*s^2)
  • M is the mass of the sun = 1.989*10^30 kg
  • r is the radius, which we want to find.

Rewriting the equation for the radius we get:

T = \sqrt{\frac{4*\pi ^2*r^3}{G*M} }\\\\r = \sqrt[3]{ \frac{T^2*G*M}{4*\pi ^2} }

Where T = 7.5 years = 7.5*(3.154*10^7 s) = 2.3655*10^8 s

Replacing the values in the equation we get:

r = \sqrt[3]{ \frac{(2.3655*10^8 s)^2*(6.67*10^{-11} m^3/(kg*s^2))*(1.989*10^{30} kg)}{4*3.14 ^2} } = 4.29*10^{11 }m

So the orbital radius is 4.29*10^11 m

If you want to learn more about orbits, you can read:

brainly.com/question/11996385

7 0
2 years ago
Which phrase describes an irregular galaxy?
viktelen [127]

Answer:b

Explanation:

Just did the test

7 0
3 years ago
Three electromagnetic waves travel through a certain point P along an x axis. They are polarized parallel to a y axis, with the
chubhunter [2.5K]

Answer:

4.846*10^{-5} sin(5*10^{14}t )

Explanation:

Frequency of each electromagnetic wave is same thus we can interfere them along X axis in Phase diagram.

In phase diagram indicate each wave as vector with amplitude as length and phase difference as angle. (shown in attachment)

Now take component of E2 and E3 amplitude along X direction.

Net amplitude of all E in X direction = 4*10^{-5} + cos(45)[ 6*10^{-6} +  6*10^{-6} ]

⇒  4.846*10^{-5}

Final resultant have no change in frequency

So , resultant is 4.846*10^{-5} sin(5*10^{14}t )

6 0
4 years ago
A 25.0-kg box of textbooks rests on a loading ramp that makes an angle α with the horizontal. The coefficient of kinetic frictio
Leni [432]

Answer:

Explanation:

a ) When the box starts to slip

static friction = mg sinα

mg cosα x μ =  mg sinα (  μ is coefficient of static friction )

Tanα =  μ  = .35

α  = 19.2°

b ) Once box starts moving , kinetic friction will start applying on it

kinetic friction = mg cos19.2 x .25

= 2.31m

net force downward = mgsin19.2 - mgcos19.2 x .25

= m ( 3.22 - 2.31 )

= .91 m

acceleration downward ( a )   = .91 m / s²

c )

v² = u² + 2 a s

= 0 + 2 x .91 x 5

= 9.1

v = 3 m / s

3 0
4 years ago
Why is rust different from the iron and oxygen that it is made of
borishaifa [10]
For the same generic reason that table salt doesn't taste or behave
like the corrosive sodium or the poisonous chlorine that it's made of.

The physical and chemical properties of compounds in general are
very different from the characteristics of any of their constituent
elements in the pure elemental state.

-- Water doesn't act anything like Hydrogen or Oxygen.

-- A candle doesn't act anything like Carbon or Hydrogen.

-- Dry ice doesn't act anything like Carbon or Oxygen.

-- DNA doesn't act anything like Hydrogen, Oxygen, Nitrogen,
   Carbon or Phosphorus.  (We are lucky.)
7 0
3 years ago
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