Which is about 30 times as far from the sun as our own planet?

How much work would be needed to lift the ball from the 2-m shelf to the 5-m shelf, and how much potential energy would it have

Stells [14]

Answer:

a) 2.94 N

b) 4.90 N

Explanation:

Let us assume that the weight of the ball is 0.98 N

Solution:

a) An object’s gravitational potential energy depends on two factors which are height and its weight (or mass). The equation for gravitational potential energy (PE) is given as:

Potential energy = weight (w) * height (h)

PE = wh

Potential energy at 2 m shelf = weight * height = 0.98 N * 2 m = 1.96 N

Potential energy at 5 m shelf = weight * height = 0.98 N * 5 m = 4.90 N

The work needed to lift the ball from the 2-m shelf to the 5-m shelf = Potential energy at 5 m shelf - Potential energy at 2 m shelf

The work needed to lift the ball from the 2-m shelf to the 5-m shelf = 4.90 N - 1.96 N = 2.94 N

b) Potential energy at 5 m shelf = weight * height = 0.98 N * 5 m = 4.90 N

6 0

3 years ago

If u blow a stream of air between two balloons that are next to each other the balloons

Naya [18.7K]

Answer:

move towards each other

Explanation:

5 0

3 years ago

Read 2 more answers

An electronics technician wishes to construct a parallelplate capacitor using rutile (k=100) as the dielectric. The area of the

My name is Ann [436]

Given k=100, Area if plate A = 1.00 cm2

$= 1 x (10-2)2 m^{2}$

Thickness of rutile $ds = t = 1.00 mm$

$= 1 x 10-3 cm$

Without any dielectric medium capacitance of a parallel plate capacitor is c = oAd

When a dielectric is placed between capacitors plates then capacitance c1 = KoAd

Here $d = t = 1 x 10-1 cm$ , $o = 8.854 x 10-12 c^{2} m^{-2} N$

Now $c1 = 100 X 8.859 X 10^{-12} X 1 X (10-2)^{21} X 10^{-2}$

$= 8.859 X 10-1910-3= 8.85 X 10-11 F= 8.85 X 10-12 F$

$C1 = 88.5 X 10-12 F$

$C1 = 88.5 PF$

Correct Option: A

What purposes serve parallel plate capacitors?

The following are some uses for parallel plate capacitors:

This kind of capacitor is utilized in rechargeable energy systems such as batteries.
These capacitors are used in systems for dynamic digital memory.
Such capacitors are used in pulsed laser and radar circuits.

To learn more about Parallel plate capacitors, visit:

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5 0

2 years ago

Q C Blaise Pascal duplicated Torricelli's barometer using a red Bordeaux wine, of density 984kg/ m³ , as the working liquid (Fig

levacccp [35]

The pressure within Earth's atmosphere is referred to as atmospheric pressure or barometric pressure. 10.701 was the height h of the wine column for normal atmospheric pressure.

<h3>What is Atmospheric pressure?</h3>

The pressure within Earth's atmosphere is referred to as atmospheric pressure or barometric pressure. The definition of the standard atmosphere is 101,325 Pa, or the same as 1013.25 millibars, 760 mm Hg, 29.9212 inches Hg, or 14.696 psi.

The force per unit area that an atmospheric column exerts is known as atmospheric pressure, often known as barometric pressure (that is, the entire body of air above the specified area). A weather indicator is atmospheric pressure. There will typically be clouds, wind, and precipitation when a low-pressure system enters a region. Fair, quiet weather is frequently a result of high pressure systems.

We have the density for the red Bordeaux wine given $\rho=965 \frac{\mathrm{kg}}{\mathrm{m}^3}$ , the atmospheric pressure on the Torricelli's barometer is given by:

$P_{a t m}=\rho g h$

Solving for the height of wine in the column we have this:

$h=\frac{P_{\text {anm }}}{\rho g}$

And replacing we have:

$h=\frac{101300 \mathrm{~Pa}}{965 \frac{\mathrm{kg}}{\mathrm{m}^3 9.81 \frac{\mathrm{m}}{\mathrm{m}^2}}}=10.701 \mathrm{~m}$$$

So the height of the red Bordeaux wine would be $\mathrm{h}=10.701 \mathrm{~m}$ . A very high value on this case if we compare with the usual values for this variable.

To learn more about Atmospheric pressure refer to:

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6 0

2 years ago

Unbalanced forces cause a change in motion

balandron [24]

Ok so here’s the thing

5 0

3 years ago