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2 years ago

Some steps to construct an angle MNT congruent to angle PQR are listed below. Step 3 is not listed:

1 answer:

5 0

Answer: D. Maintaining the same width of the compass as AB, draw an arc from point X such that it intersects the arc drawn from N in a point Y.

Took the test.

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The sales tax in your city is 8.8%, point, 8, percent, and an item costs $63$, before tax.

PIT_PIT [208]

You would pay $5.54 on that item.

Step-by-step explanation:

Given,

Cost of item = $63

Sales tax rate = 8.8%

Amount of sales tax = 8.8% of cost of item

Amount of sales tax = $\frac{8.8}{100}*63$

Amount of sales tax = $\frac{554.4}{100}$

Amount of sales tax = $5.54

You would pay $5.54 on that item.

Keywords: percentage, division

Learn more about percentages at:

#LearnwithBrainly

8 0

3 years ago

Please help me answer the question 9 though 10

olchik [2.2K]

Answer:

9) slope of AC = slope of FH

Equation of the line is y = - x + 5

10) Area = 320

Step-by-step explanation:

For 9, the only thing similar IS the slope of the hypotenuse because the triangles are along the same line. Unless they're asking for the equation of the line, then that's just using the point slope equation which is:

y = - x + 5

For 10, just multiply 4 and 5 by 4 to get 16 and 20. Then multiply 16 and 20 to get 320.

8 0

2 years ago

What is 10 times as many as

Talja [164]

Answer:

To answer this question, more information needs to be disclosed.

3 0

2 years ago

Can anyone help me integrate :

worty [1.4K]

Rewrite the second factor in the numerator as

$2x^2+6x+1=2(x+2)^2-2(x+2)-3$

Then in the entire integrand, set $x+2=\sqrt3\sec t$ , so that $\mathrm dx=\sqrt3\sec t\tan t\,\mathrm dt$ . The integral is then equivalent to

$\displaystyle\int\frac{(\sqrt3\sec t-2)(6\sec^2t-2\sqrt3\sec t-3)}{\sqrt{(\sqrt3\sec t)^2-3}}(\sqrt3\sec t)\,\mathrm dt$
$=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\sqrt{\sec^2t-1}}\,\mathrm dt$
$=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\sqrt{\tan^2t}}\,\mathrm dt$
$=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{|\tan t|}\,\mathrm dt$

Note that by letting $x+2=\sqrt3\sec t$ , we are enforcing an invertible substitution which would make it so that $t=\mathrm{arcsec}\dfrac{x+2}{\sqrt3}$ requires $0\le t$ or $\dfrac\pi2$ . However, $\tan t$ is positive over this first interval and negative over the second, so we can't ignore the absolute value.

So let's just assume the integral is being taken over a domain on which $\tan t>0$ so that $|\tan t|=\tan t$ . This allows us to write

$=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\tan t}\,\mathrm dt$
$=\displaystyle\int(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\csc t\,\mathrm dt$

We can show pretty easily that

$\displaystyle\int\csc t\,\mathrm dt=-\ln|\csc t+\cot t|+C$
$\displaystyle\int\sec t\csc t\,\mathrm dt=-\ln|\csc2t+\cot2t|+C$
$\displaystyle\int\sec^2t\csc t\,\mathrm dt=\sec t-\ln|\csc t+\cot t|+C$
$\displaystyle\int\sec^3t\csc t\,\mathrm dt=\frac12\sec^2t+\ln|\tan t|+C$

which means the integral above becomes

$=3\sqrt3\sec^2t+6\sqrt3\ln|\tan t|-18\sec t+18\ln|\csc t+\cot t|-\sqrt3\ln|\csc2t+\cot2t|-6\ln|\csc t+\cot t|+C$
$=3\sqrt3\sec^2t-18\sec t+6\sqrt3\ln|\tan t|+12\ln|\csc t+\cot t|-\sqrt3\ln|\csc2t+\cot2t|+C$

Back-substituting to get this in terms of $x$ is a bit of a nightmare, but you'll find that, since $t=\mathrm{arcsec}\dfrac{x+2}{\sqrt3}$ , we get

$\sec t=\dfrac{x+2}{\sqrt3}$
$\sec^2t=\dfrac{(x+2)^2}3$
$\tan t=\sqrt{\dfrac{x^2+4x+1}3}$
$\cot t=\sqrt{\dfrac3{x^2+4x+1}}$
$\csc t=\dfrac{x+2}{\sqrt{x^2+4x+1}}$
$\csc2t=\dfrac{(x+2)^2}{2\sqrt3\sqrt{x^2+4x+1}}$

etc.

3 0

2 years ago

Will upvote<br><br> 4,7,12,19,31,... does this classify as a arithmetic, geometric, or neither

spayn [35]

To find if a series is either geometric or arithmetic:
it must satisfy this property:

Arithmetic:

a(n+1) - a(n) = const

Geometric:

a(n+1)/a(n) = const

In your case:

r1 = 7 -4 = 3

r2 = 12 - 7 = 5

r1 != r2 (not arirthmetic)

Geometric check:

r1 = 7/4

r2 = 12/7

r1 != r2 (not Geometric)

so neither.

8 0

2 years ago