Answer: The period doubles.
Explanation: this is a question on the relationship between the period (T) of a loaded spring and it mass (m), the formulae relating both quantities is given below.
T =2π * √m/k
Where T= period, m= mass and k = spring constant.
By squaring both sides, we have
T² = 4π² * m/k
T² = (4π²/k) * m
The expression (4π²/k) is a constant, hence
T² = K *m... This implies that square of period is proportional to mass.
Hence
(T1)²/m1 = (T2)²/m2
From the question, m2 =4m1 and we are to find T2.
(T1)²/m1 = (T2)²/4m1
(T1)² = (T2)²/4
4(T1)² = (T2)²
T2 =√4(T1)²
T2 = 2T1
this implies that T2 is twice or double T1