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mars1129 [50]
4 years ago
12

Which is greater 2.5 or 6?

Mathematics
1 answer:
Semmy [17]4 years ago
8 0
6 is greater than 2.5
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The number cube is rolled and a coin is tossed .How can you sketch a tree diagram to represent the sample space ?
nevsk [136]

Answer:

Refer to the diagram in the attachment.

Step-by-step explanation:

There are two events here: the first one is the number on the cube. The second one is the outcome of the coin toss. This tree should contain two columns, one for each event.

Start with the first column. Let N be the outcome of the number cube. There are six possible values: \text{$1,\, 2,\, 3,\, 4,\, 5,$ and $6$}. That corresponds to six branches, one for each outcome.

Continue to the second column. Let C be the outcome of the coin toss. No matter which number was obtained for N, there would always be two possible outcomes for

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3 years ago
How do you ordered pair that represents a solutions to the system of linear inequalities below?
ELEN [110]

Answer:

x=No (Minimum)

Step-by-step explanation:

Hope this helps

4 0
3 years ago
The population of a city in 2005 was 18,000. By 2010, the city’s population had grown to 45,000. Economists have determined that
steposvetlana [31]

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120,000

Step-by-step explanation:

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4 0
4 years ago
Read 2 more answers
Given the points (2,k) (2,k) and (0,−6) (0,−6) , for which values of k would the distance between the points be 5 – √ 5
11Alexandr11 [23.1K]

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have:

(2,\ k)\to x_1=2,\ y_1=k\\(0,\ -6)\to x_2=0,\ y_2=-6\\d=5-\sqrt5

Substitute:

\sqrt{(0-2)^2+(-6-k)^2}=5-\sqrt5\\\\\sqrt{(-2)^2+[-(6+k)]^2}=5-\sqrt5\\\\\sqrt{4+(6+k)^2}=5-\sqrt5\ \ \ \ \ |^2\\\\4+(6+k)^2=(5-\sqrt5)^2\ \ \ \ |use\ (a-b)^2=a^2-2ab+b^2

4+(6+k)^2=5^2-2\cdot5\cdot\sqrt5+(\sqrt5)^2\\\\4+(6+k)^2=25-10\sqrt5+5\ \ \ \ |-4\\\\(6+k)^2=26-10\sqrt5\to6+k=\pm\sqrt{26-10\sqrt5}\ \ \ \ |-6\\\\\boxed{k=-6-\sqrt{26-10\sqrt5}\ \vee\ k=-6+\sqrt{26-10\sqrt5}}

If d=\sqrt5, then:

\sqrt{4+(6+k)^2}=\sqrt5\ \ \ \ |^2\\\\(\sqrt{4+(6+k)^2})^2=(\sqrt5)^2\\\\4+(6+k)^2=5\ \ \ \ |-4\\\\(6+k)^2=1\to 6+k=\pm\sqrt1\\\\6+k=\pm1\ \ \ \ |-6\\\\\boxed{k=-7\ \vee\ k=-5}

3 0
3 years ago
Please explain how to do this and still get the answer 16. Thank you!
Kitty [74]
(j-3)8=104
8j-24=104
8j=128
j=16

5 0
3 years ago
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