3 years ago

Which of the following is equivalent to: 6 - 2x > 3(4x - 2)?

Mathematics

1 answer:

ValentinkaMS [17]3 years ago

5 0

Answer:

14x < 12

Step-by-step explanation:

Given

6 - 2x > 3(4x - 2) ← distribute right side

6 - 2x > 12x - 6 ( subtract 12x from both sides )

6 - 14x > - 6 ( subtract 6 from both sides )

- 14x > - 12

Multiply both sides by - 1, reversing the inequality symbol as a consequence of multiplying by a negative quantity, thus

14x < 12

You might be interested in

Write the equation of the line that is perpendicular to y= -0.25x and that passes through the point (-4,0)

Andrei [34K]

I think this should be right

8 0

3 years ago

When solving inequalities the inequality is reversed when:

Anettt [7]

When we multiply or divide an inequality by a negative integer.

7 0

2 years ago

Read 2 more answers

Name the sets of numbers to which the given number belongs.<br><br> -4

aivan3 [116]

The answer to your question is B.

8 0

4 years ago

Help please !!!!!!!!!!!!!!

MAVERICK [17]

Answer:

two of the points are (0,5) and (2.5,0)

7 0

3 years ago

Read 2 more answers

The point P=\left(-\frac{1}{2},\,\, y\right)P=(− 2 1 ,y) lies on the unit circle shown below. What is the value of yy in simpl

sukhopar [10]

Answer:

$y = \frac{\sqrt{3}}{2}} \\\\$

Step-by-step explanation:

We are given a point P which lies on a unit circle

P = (-½, y)

Where x coordinate is -½ and y coordinate is y.

We are asked to find the value of y in simplest form.

Recall that a unit circle has a radius of 1 and is centered at the origin that is (0,0).

The equation of the unit circle is given by

$x^{2} + y^{2} = 1$

Since the point P lies on a unit circle, we can substitute this point into the equation of unit circle and get the value of y.

Substitute x = -½ and y = y

$(-\frac{1}{2} )^{2} + y^{2} = 1\\\\(\frac{1}{4} ) + y^{2} = 1\\\\y^{2} = 1 - \frac{1}{4} \\\\y^{2} = \frac{3}{4} \\\\y = \pm \sqrt{\frac{3}{4}} \\\\y = \pm \frac{\sqrt{3}}{2}} \\\\$

Assuming that the given point P lies in the 2nd quadrant, the value of y will be positive.

$y = \frac{\sqrt{3}}{2}} \\\\$

Therefore, the coordinates of the point P are

$P =( -\frac{1}{2} , \frac{\sqrt{3}}{2}}) \\\\$

6 0

3 years ago