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yKpoI14uk [10]
3 years ago
15

You originally draw a design for an art contest on a 3 in. x 5 in. card. The second phase of the contest requires the drawing to

be transferred to an 8.5 in x 11 in. standard sheet of paper and utilize as much of the space on the paper as possible. You determine that the largest size one of the dimensions of your drawing can be is 10.5 in. What is the length of the other dimension if the two drawings are similar? Type your exact answer in the blank without the units, and round to the nearest tenths.
Mathematics
2 answers:
Cerrena [4.2K]3 years ago
4 0
Set up an equality with proportional relations:

x/10.5=3/5  multiply both sides by 10.5

x=31.5/5

x=6.3
Ksju [112]3 years ago
3 0
So for a 3 by 5 to be enlarged to where one side is 10.5, it must have been multiplied by 2.1 or it won't fit onto the new paper. So you multiply the other number, 3, by 2.1 and get the answer 6.3
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A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th
Burka [1]

Answer:

Confidence interval : 21.506 to 24.493

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = \bar{x}=\frac{\sum x}{n}

Sample mean = \bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}

Sample mean = \bar{x}=23

Sample standard deviation = \sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}

Sample standard deviation = \sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}

Sample standard deviation= s = 1.72

Degree of freedom = n-1 = 20-1 -19

Critical value of t using the t-distribution table t_{\frac{\alpha}{2} = 3.883

Formula of confidence interval : \bar{x} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}}

Substitute the values in the formula

Confidence interval : 23 \pm 1.73 \times \frac{1.72}{\sqrt{20}}

Confidence interval : 23 -3.883 \times \frac{1.72}{\sqrt{20}} to 23 + 3.883 \times \frac{1.72}{\sqrt{20}}

Confidence interval : 21.506 to 24.493

Hence Confidence interval : 21.506 to 24.493

3 0
3 years ago
Read 2 more answers
Mrs. Hoffnagle's class is practicing skip counting by 30's . The first student said 30, the second said 60, and the third said 9
nadezda [96]

Answer:

120

Step-by-step explanation:

It’s like counting by 3’s and adding a 0

3,6,9,12

30,60,90,120

3 0
2 years ago
How do you solve (20.3×0.7)×7 with pemdas step by step
JulijaS [17]
TheProfessor35's answer is correct, but here's a step by step as you asked. PEMDAS stands from Parentheses Exponents Multiplication Division Addition Subtraction. So, in the problem, you first solve the part inside the parentheses. Are there exponents? No, so we move on. Anything need to be multiplied? Yes, 20.3 x 0.7. That gives us 14.21. Now, there is nothing left in the parentheses to be divided, added, or subtracted, so we move on to the outside. We multiply 14.21 by 7 and get 99.47.
3 0
3 years ago
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The coordinates of AABC are A(0,0), B(7,0), and C(1,5). Triangle A'B'C'is the image of AABC rotated counterclockwise about the o
prisoha [69]

Answer:

i dont know

Step-by-step explanation:

that is too hard

3 0
2 years ago
A right triangle has one 90 degree or blank angle
STALIN [3.7K]
A right angle has one 90° angle, and the sum of the angles of any triangle is  always equals 360°.
4 0
3 years ago
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