Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
Answer:
D
Step-by-step explanation:
The area and the radius of a sphere are related by the formula:
A=4πr^2
Let’s say this is A1 and r1
Now the radius is tripled. This means r2 = 3r1
The new area thus becomes: A = 4 * (3r)^2 * π = 36πr^2
Comparing A1 and A2 , we can see that A2 = 9A1
Tell your cousin good luck and that the answer is 5 :)
Answer:
Step-by-step explanation:
So they can get prepared for the future
Answer:
1=1 times 2/2 1 + 2=2 times 3/2 1 +2+3=3 times 4/2 1+2+3+4=4 times 5/2 1+2+3+4+5=5 times 6/2
