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Assoli18 [71]
3 years ago
11

The Calorie and I KULUT 3. What quantity has the units J/(g•°C)?

Chemistry
1 answer:
zloy xaker [14]3 years ago
4 0

Specific heat capacity

Explanation:

The quantity that has units J/(g•°C) is specific heat capacity.

What is specific heat capacity?

  • This is the amount of heat required to raise the temperature of a 1g substance by 1°C.
  • It is simply the heat applied to cause a unit change in the temperature of a substance.
  • Metals have low specific heat because they are good conductors.
  • Non-metals have a high specific heat capacity.

learn more:

Specific heat brainly.com/question/7210400

#learnwithBrainly

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A gaseous hydrogen and carbon containing compound is decomposed and formed to contain 82.66% carbon and 17.34% hydrogen by mass.
Romashka [77]

Explanation:

Mole percentage of carbon = \frac{percentage given}{molar mass of carbon}

                                              = \frac{82.66}{12}

                                              = 6.89

Mole percentage of hydrogen = \frac{percentage given}{molar mass of hydrogen}

                                               = \frac{17.34}{1}

                                               = 17.34

Now, dividing mole percentage of both the atoms by 6.89.

Then,     C = 1 and H = \frac{17.34}{6.89} = 2.5

Hence, empirical formula is C_{2}H_{5}.

As, it is given that P = 556 mm Hg. Convert mm Hg into atm as follows.

                        \frac{556 mm Hg \times atm}{760 mm Hg}

                             = 0.7316 atm

Volume is given as 158 mL. So, in liter volume is \frac{158}{1000} equals 0.158 L.

According to ideal gas equation, PV = nRT

                      0.7316 atm \times 0.158 L = \frac{mass}{molar mass} \times 0.082 atm L/mol K \times 298 K          

                       0.7316 atm \times 0.158 L = \frac{0.275 g}{molar mass} \times 0.082 atm L/mol K \times 298 K        

                   molar mass = 58.2 g

Hence, molecular weight of C_{2}H_{5} is 12 \times 2 + 5 = 29.

Therefore, (C_{2}H_{5})_{n} = 58

                               29 × n = 58

                                   n = 2

Thus, molecular formula of the compound is C_{4}H_{10}.

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Explanation:

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