Answer:
Solution that is 0.100 M CH3COOH (acetic acid)
and 0.100 M NaCH3COO (sodium acetate)
Find pH of buffer solution:
CH3COOH(aq) + H2O ↔ CH3COO-
(aq) + H3O+(aq)
[CH3COOH] [CH3COO-
] [H3O+]
initial 0.100 0.100 ≈0
-x x x
equil 0.100 – x 0.100 + x xFind pH of buffer solution:
CH3COOH(aq) + H2O ↔ CH3COO-
(aq) + H3O+(aq)
Ka = [CH3COO-
][H3O+
]
[CH 3COOH] = (.100 + x)x
(.100 - x) = 1.8 x 10-5
x = 1.80 x 10-5 M
pH = 4.7
Explanation:
Answer:
This is the answer
Explanation:
charges passed = current x time = 10 x 3 x 60
= 1800 C
mole of charge = 1800 / 96500
= .01865 moles
Au+3 contains 3 positive charges
3 mole of charge will deposit 1 mole of Au .01865 moles will deposit .01865 / 3 mole
= 6.2167 x 10-3 moles.
In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
Answer:
The bronsted- Lowry acid is H₂PO₄⁻
Explanation:
Bronsted-Lowry acid donates a proton (H⁺)
H₂PO₄⁻ + OH⁻ → HPO₄²⁻ + H₂O
In the reaction above, H₂PO₄⁻ is donating the proton to OH⁻ resulting in H₂O and the deprotonated species. This makes it a bronsted-Lowry acid.
