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MatroZZZ [7]
3 years ago
15

__________ occurs when something interferes with the conduction of sound vibrations from the outer and middle ear to the inner e

ar. A. Sensorineural hearing loss B. Conductive hearing loss C. An ear infection D. Otitis media
SAT
2 answers:
geniusboy [140]3 years ago
8 0

Answer:

Conductive hearing loss

Explanation:

Helen [10]3 years ago
6 0

Answer:

B. Conductive hearing loss

Explanation:

Conductive hearing loss refers to a problem transfering sound waves because of a blockage or damage in the outer ear, middle ear or tympanic membrane. This problem can be treated with medicines or surgery and hearing can be fully restored. Conductive hearing loss can be caused for several things like an accumulation of ear wax, a middle ear infection or a chronic infection. Because of this, the answer is conductive hearing loss.

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What values of c and d would make the following expression represent a real number? i(2 3i)(c di) c = 2, d = 3 c = –2, d = 3 c =
Olegator [25]

Complete question:

<em>What values of c and d would make the following expression represent a real number? i(2 + 3i)(c + di) </em>

<em>choices: A)c = 2, d = 3 B)c = –2, d = 3 C)c = 3, d = –2 D)c = –3, d = –2</em>

<em />

<em>Option D</em><em> is correct. </em> The value of c and d for the expression to be real are -3 and -2 respectively

Given the expression

i(2 + 3i)(c + di)

Expand the expression

=i(2 + 3i)(c + di)\\=(2i+3i^2)(c+di)\\=(2i+3(-1))(c+di)\\=(2i-3)(c+di)\\=2ic+2di^2-3c-3di\\=2ic-2d-3c-3di

Collect the like terms

=2ic-3di-2d-3c

For the resulting function to be real, then the imaginary part must be zero i.e.

2ic-3di=0\\2ci = 3di\\2c = 3d\\c=\frac{3d}{2}\\

If d = -2, then;

c=\frac{3(-2)}{2}\\c=\frac{-6}{2}\\c= -3

Hence the value of c and d for the expression to be real are -3 and -2 respectively.

Learn more here: brainly.com/question/4244460

8 0
3 years ago
30 =90 what is 1 hundred
marusya05 [52]

Answer:

720

Explanation:

40:180

50:270

60:360

70:450

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100:720

5 0
4 years ago
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