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2 years ago

Monica made a mistake. She can select the undo command or use the shortcut to quickly correct her mistake. True False

SAT

2 answers:

leonid [27]2 years ago

5 0

This is true, she can

nordsb [41]2 years ago

5 0

Answer:

Explanation:

<em>In the question given, Monica can make use of the undo command to correct her mistake.</em>

<em>The Undo command erases the last change made to a document, that is taking it back to a previous state.</em>

<em>In other application programs, such as Microsoft word, undo will negate the command done last to the file being worked on. without fear of making mistakes, users can explore and work with the possibility of undo, because they can be undone easily.</em>

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17.3 subtracting polynomial expressions answer key

yaroslaw [1]

An example of 17.3 subtracting polynomial expressions question is solve for 2q² - q - 8) - (2 q² + q - 4).

<h3>What is polynomial expressions?</h3>

A polynomial is known to be a type of an expression that is made up of variables, constants and exponents. They are often combined using the mathematical terms such as addition, subtraction, etc.

2 q² - q - 8) - (2 q² + q - 4)

= (2 q² - q - 8) + (-2 q² - q + 4)

Then you have to rewrite subtraction as addition and then Group like terms together;

= (2 q² - 2 q²) + (-q - q) + (-8 + 4)

= -2q - 4

Learn more about polynomial from

brainly.com/question/2833285

7 0

2 years ago

In air, a sound wave with a frequency of 196 hz has a wavelength of about 1.76 meters. what is the wavelength of a wave if the f

Aloiza [94]

The wavelength of the sound wave if the frequency is increased to the given value is 0.44m.

Given the data in the question;

Frequency of sound wave a; $f_a = 196Hz = 196s^{-1}$

Wavelength of sound wave a; $\lambda _a = 1.76m$

Speed of sound wave; $v =\ ?$

Frequency of sound wave b; $f_b = 784Hz = 784s^{-1}$

Wavelength of sound wave b; $\lambda _b = ?$

<h3>Wavelength</h3>

Wavelength is simply the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.

It is expressed as;

$\lambda = \frac{v}{f}$

Where v is velocity and f is frequency.

First, we calculate the velocity of the sound wave in air from sound wave a.

$\lambda = \frac{v}{f}\\ \\1.76m= \frac{v}{196s^{-1}}\\\\v = 1.76m * 196s^{-1}\\\\v = 344.96m/s$

Now, we determine the wavelength of sound wave b using the velocity of sound wave in air calculated above.

$\lambda = \frac{v}{f}\\ \\\lambda = \frac{344.96m/s}{784s^{-1}}\\\\\lambda = 0.44m$

Therefore, the wavelength of the sound wave if the frequency is increased to the given value is 0.44m.

Learn more about wavelength: brainly.com/question/27120701

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1 year ago

At stp both diamond and graphite are solids composed of carbon atoms. These solids have.

AfilCa [17]

These solids, diamond and graphite are first naturally occurring inorganic substances and have an orderly internal structure and characteristic chemical composition, crystal form, and physical properties.

<h3>Standard temperature and pressure of diamond and graphite</h3>

At standard temperature and pressure, the two minerals; diamond and graphite which are both composed of carbon atoms are Allotropes of Carbon. Additionally, peculiar difference between them exists in the delocalization of electrons in one as opposed to the other.