Lizzie has 18 dimes and 12 quarters
<em><u>Solution:</u></em>
Let "d" be the number of dimes
Let "q" be the number of quarters
We know that,
value of 1 dime = $ 0.10
value of 1 quarter = $ 0.25
Given that LIzzie has 30 coins
number of dimes + number of quarters = 30
d + q = 30 ---- eqn 1
Also given that the coins total $ 4.80
number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 4.80

0.1d + 0.25q = 4.8 ------ eqn 2
Let us solve eqn 1 and eqn 2
From eqn 1,
d = 30 - q ---- eqn 3
Substitute eqn 3 in eqn 2
0.1(30 - q) + 0.25q = 4.8
3 - 0.1q + 0.25q = 4.8
0.15q = 1.8
<h3>q = 12</h3>
From eqn 3,
d = 30 - 12
<h3>d = 18</h3>
Thus she has 18 dimes and 12 quarters
<span>THE GIVEN QUESTION;
7x -3(4x-8) < 6x +12 - 9x
THE GIVEN INTERVAL OF X IS FROM [4,8] SO THE VALUE OF X ={4,5,6,7,8}
THE GIVEN QUESTION CAN BE EVALUATED TO
7x - 12x+ 24 < 12 - 3x
-5x + 24 < 12 - 3x //USING BODMAS RULE
NOW SUBSTITUTING THE VALUE OF X:
1) X=4 SOL: 4<0
2) X=5 SOL: -1<-3
3) X=6 SOL: -6<-6
4) X=7 SOL: -11<-9
5) X=8 SOL: -16<-12
HENCE THE VALUE OF X=7,8 SATISFY THE GIVEN INEQUALITY</span>
Answer:
289/216
Step-by-step explanation:
add the parentheses first
(2/3+3/4)×(3/6+4/9)=
17/12×17/18
then multiply
17/12×17/18=
286/216
Answer:
36
Step-by-step explanation:
He multiplied the four and the three first when he multiplied the equation together. However, according to the order of the operations, he was supposed to square three first. 3^2 = 9. Then multiplied 9*4 = 36.