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kotykmax [81]
3 years ago
6

The outside dimensions of a living room are 13' 0" x 22' 0". If the wall thickness is 5 1/8" , what are the inside dimensions of

the living room?
A. 12' 13/4" x 21' 13/4"
B. 7' 101/2" x 16' 101/2"
C. 12' 71/8" x 21' 71/8"
D. 12' 67/8" x 21' 67/8"

Mathematics
1 answer:
garri49 [273]3 years ago
4 0

it would be C 12' 71/8" x 21' 71/8"

and sorry for what I said and did

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In a study to estimate the proportion of residents in a certain city and its suburbs who favor the construction of a nuclear pow
leva [86]

Answer:

The test statistic z = z = 2.368 >1.97 (at 5% level of significance)

we rejected null hypothesis at 5% level of significance

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Step-by-step explanation:

Given data In a study to estimate the proportion of residents in a certain city and its suburbs who favor the construction of a nuclear power plant, it is found that 63 of 100 urban residents

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The second  sample proportion p_{2} = \frac{59}{125}  = 0.472

Given the sample sizes are n₁ = 100 and n₂ =125

<u>Null hypothesis(H₀):</u>-there is no significant difference between the proportions of urban and suburban residents who favor construction of the nuclear plant.

<u>Alternative hypothesis: H₁</u>

There is  significant difference between the proportions of urban and suburban residents who favor construction of the nuclear plant.

<u>Level of significance</u>:-

∝ =0.05

Tabulated value z=1.96

<u>Test statistic</u>

<u></u>z = \frac{p_{1}-p_{2}  }{\sqrt{pq(\frac{1}{n_{1} } +\frac{1}{n_{2} } )} }<u></u>

where p = \frac{n_{1}p_{1} +n_{2}p_{2}  }{n_{1} +n_{2} }         q = 1- p

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q = 1-p = 1 - 0.542 = 0.458

The test statistic

z = \frac{0.63-0.472}{\sqrt{0.542X0.458}(\frac{1}{100}+\frac{1}{125}   )}

on simplification , we get

z = 2.368 >1.97 (at 5% level of significance)

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<u>Conclusion</u>:-

There is  significant difference between the proportions of urban and suburban residents who favor construction of the nuclear plant.

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