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3 years ago

6

For every 1.0 mole of glycine in the sample, how many molecules of methionine are present? (for help performing calculations wit

h numbers expressed in scientific notation, try this exercise.)

1 answer:

krok68 [10]3 years ago

3 0

1.08 X 10^21 molecules

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Write the step by step process of digestion in ruminants using 4 square method.

Vaselesa [24]

The digestion process in Ruminants begins by chewing and swallowing their food.

<h3>What are ruminants?</h3>

A ruminant is any herbivorous animal that has a stomach with four compartments, which are tasked with acquiring nutrients from plant-based food by fermenting it prior to digestion.

The digestion process in Ruminants begins by chewing and swallowing their food. Ruminants do not completely chew the food they eat, but just consume or gulp as much they can and then swallow the food. This is actually an adaptation by which these animals have evolved to spend as little time as possible feeding so that they are not hunted down by any predators while they are eating.

As mentioned earlier, the stomach of these Ruminants is divided into 4 chambers – rumen, reticulum, omasum, and the abomasum.

The process of digestion begins with the first two chambers of the stomach, the rumen and reticulum by softening the ingested matter. Later the microbes present in the rumen produces the cellulase enzymes required to digest the cellulose.

Once the plant fibres have been broken down to provide vitamins, proteins, and other organic acids, the nutrients are absorbed into the animal’s bloodstream.

Coarse plants are sent further into the next chamber for further digestion. Here is where the further bacterial action takes place and the food is formed into soft chunks called the cud.

This cud produced is regurgitated back into the animal’s mouth where it can be chewed again. The saliva of the cow greatly aids in digesting the cud.

After chewing, the food bypasses the two chambers of the stomach and directly enters the third chamber. The walls of the third chamber mash and compact the food molecules further, and then pass it to the fourth chamber – the abomasum.

The final digestion in the stomach is carried by the abomasum and then passed to the intestine.

Learn more about the ruminants here:

brainly.com/question/26752412

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2 years ago

What is the total number of atoms in 1.0 mole of

emmainna [20.7K]

D. 18 x 10^23 is the total number of atoms in 1.0 mole of CO2

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4 years ago

What is the maximum number of electrons that can go into each of the following sub levels

zaharov [31]

The s sublevel has just one orbital, so can contain 2 electrons max. The p sublevel has 3 orbitals, so can contain 6 electrons max. The d sublevel has 5 orbitals, so can contain 10 electrons max. And the 4 sublevel has 7 orbitals, so can contain 14 electrons max.

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3 years ago

(a) The mass density of a gaseous compound was found to be 1.23 kg m^−3 at 330 K and 20 kPa. What is the molar mass of the compo

Luden [163]

Answer:

The molar mass of the compound is:- 168.82 g/mol

The molar mass of the gas is:- 16.38 g/mol

Explanation:

(a)

Using ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Also,

Moles = mass (m) / Molar mass (M)

Density (d) = Mass (m) / Volume (V)

So, the ideal gas equation can be written as:

$PM=dRt$

Given that:-

Pressure = 20 kPa = 20000 Pa

The expression for the conversion of pressure in Pascal to pressure in atm is shown below:

P (Pa) = $\frac {1}{101325}$ P (atm)

20000 Pa = $\frac {20000}{101325}$ atm

Pressure = 0.1974 atm

Temperature = 330 K

d = 1.23 kg/m³ = 1.23 g/L

Molar mass = ?

Applying the equation as:

0.1974 atm × M = 1.23 g/L × 0.0821 L.atm/K.mol × 330 K

⇒M = 168.82 g/mol

<u>The molar mass of the compound is:- 168.82 g/mol</u>

(b)

Given that:

Pressure = 152 Torr

Temperature = 298 K

Volume = 250 cm³ = 0.25 L

Using ideal gas equation as:

$PV=nRT$

R = $62.3637\text{torr}mol^{-1}K^{-1}$

Applying the equation as:

152 Torr × 0.25 L = n × 62.3637 L.torr/K.mol × 298 K

⇒n = 0.002045 moles

Given that :

Mass of the gas = 33.5 mg = 0.0335 g

Molar mass = ?

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$0.002045\ moles
= \frac{0.0335\ g}{Molar\ mass}$

<u>The molar mass of the gas is:- 16.38 g/mol</u>

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3 years ago

Find the amount of heat needed to raise the temperature of a 4g of a substance from 20°C to

Lostsunrise [7]

Answer:

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Explanation:

3 0

3 years ago