The radii of most atoms are actually measured in the Ǻ, or Angstrom. We can do it in nanometers too, however.
<span>First, we take the radius of the smallest atom, He (Helium). Atomic radius = .031 nm. The largest atom, stable atom is Fr (Francium), with atomic radius = .27 nm. </span>
<span>Therefore, the typical atomic radius is between .031 and .27 nm.</span>
Answer:
A) 9.60 g
B) 19.2 g
C) 28.8 g
Explanation:
A) Elemental oxygen mass is 16.00 g/mol, so in 0.600 mol of elementar oxygen there is 9.60 g
0.600 mol x 16.00 g/mol=9.60 g
B) Oxygen molecular mass is 32.00 g/mol, so in 0.600 mol of oxygen molecules there is 19.2 g
0.600 mol x 32.00 g/mol=19.2 g
C) Ozone molecular mass is 48.00 g/mol, so in 0.600 mol of oxygen molecules there is 28.8 g
0.600 mol x 48.00 g/mol=28.8 g
The right answers are: B) and C)
Answer:
0.373 moles of ammonium carbonate
Explanation:
To solve this question we must find the molar mass of ammonium carbonate. With the molar mass and the mass we can find its moles, as follows:
(NH₄)₂CO₃ contains: 2 moles N, 8 moles H, 1 mole C, 3 moles O. Molar mass:
2N = 14.0g/mol*2 = 28.0
8H = 1.0g/mol*8 = 8.0
1C = 12.0g/mol*1 = 12.0
3O = 16.0g/mol*3 = 48.0
Molar mass: 28.0 + 8.0 + 12.0 + 48.0 = 96.0g/mol
The moles of ammonium carbonate in 35.8g are:
35.8g * (1mol / 96.0g) =
<h3>0.373 moles of ammonium carbonate</h3>
