Question

PLEASE HELP WILL GIVE BRAINLIEST!!!!! A survey asked students whether they have any siblings and pets.

Answer 1

The answrr is B, 60%. 45/75 equals 60, so it should be 60%.

Answer 2

Answer:

Option B.

Step-by-step explanation:

The given table represents the relative frequency.

Let A and B represent the following events.

A : Student does not have a sibling

B :  Students has a pet.

Then intersection of A and B (A∩B) denotes the event that the student does not have a sibling but has a pet.

Using the given table it is clear that

P(A∩B) = 0.15

We need to find the probability that the student does not have a pet given that student has a sibling. It means we need to find the value of P(B|A).

Formula for conditional probability:

$P(B|A)=\dfrac{P(A\cap B)}{P(A)}$

Substitute the given values.

$P(B|A)=\dfrac{0.15}{0.25}$

$P(B|A)=\dfrac{3}{5}$

$P(B|A)=0.6=60\%$

The probability that the student does not have a pet given that student has a sibling is 60%.

Therefore, the correct option is B.