PLEASE HELP WILL GIVE BRAINLIEST!!!!! A survey asked students whether they have any siblings and pets.
2 answers:
Answer:
Option B.
Step-by-step explanation:
The given table represents the relative frequency.
Let A and B represent the following events.
A : Student does not have a sibling
B : Students has a pet.
Then intersection of A and B (A∩B) denotes the event that the student does not have a sibling but has a pet.
Using the given table it is clear that
P(A∩B) = 0.15
We need to find the probability that the student does not have a pet given that student has a sibling. It means we need to find the value of P(B|A).
Formula for conditional probability:
Substitute the given values.
The probability that the student does not have a pet given that student has a sibling is 60%.
Therefore, the correct option is B.
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Answer:
a. the motion is positive in the time intervals:
The motion is negative in the time interval: (2,6)
b. S=7 m
c. distance=71m
Step-by-step explanation:
a. In order to solve part a. of this problem, we must start by determining when the velocity will be positive and when it will be negative. We can do so by setting the velocity equation equal to zero and then testing it for the possible intervals:
so let's solve this for t:
and now we factor it again:
(t-6)(t-2)=0
so we get the following answers:
t=6 and t=2
so now we can build our possible intervals:
and now we test each of the intervals on the given velocity equation, we do this by finding test values we can use to see how the velocity behaves in the whole interval:
[0,2) test value t=1
so:
v(1)=15 m/s
we got a positive value so the object moves in the positive direction.
(2,6) test value t=3
so:
v(3)=-9 m/s
we got a negative value so the object moves in the negative direction.
test value t=7
so:
v(1)=15 m/s
we got a positive value so the object moves in the positive direction.
the motion is positive in the time intervals:
The motion is negative in the time interval: (2,6)
b) in order to solve part b, we need to take the integral of the velocity function in the given interval, so we get:
so we get:
which simplifies to:
so now we evaluate the integral:
s=7 m
for part c, we need to evaluate the integral for each of the given intervals and add their magnitudes:
[0,2)
s(t)=\int\limits^2_0 {(3t^{2}-24t+36)} \, dt
so we get:
which simplifies to:
so now we evaluate the integral:
s=32 m
(2,6)
s(t)=\int\limits^6_2 {(3t^{2}-24t+36)} \, dt
so we get:
which simplifies to:
so now we evaluate the integral:
s=-32 m
(6,7)
s(t)=\int\limits^7_6 {(3t^{2}-24t+36)} \, dt
so we get:
which simplifies to:
so now we evaluate the integral:
s=7 m
and we now add all the magnitudes:
Distance=32+32+7=71m