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quester [9]
3 years ago
8

Assume that each of the n trials is independent and that pis

Mathematics
1 answer:
sukhopar [10]3 years ago
6 0
P(x)=n!/(n-x)!x!= 15!/12!*3!
P(x)=15*14*13*12!/12!*3*2*1=455
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Write the quadratic equation whose roots are 3 and 1, and whose leading coefficient is 1
Serhud [2]

Answer:

x² - 4x + 3 = 0

Step-by-step explanation:

given roots x = a and x = b then the corresponding factors are

(x - a) and (x - b)

the equation is then the product of these factors , that is

(x - a)(x - b) = 0

given

roots x = 3 and x = 1 , then factors are (x - 3) and (x - 1) , then

(x - 3)(x - 1) = 0 ← expand factors using FOIL

x² - 4x + 3 = 0

6 0
2 years ago
0.72 is ten times as much as ________. *
RideAnS [48]

Answer:

0.072 or .072

Step-by-step explanation:

0.72 is ten times as much as 0.072.

0.072 times 10 is .72.

0.72 / 10 = 0.072 .

5 0
2 years ago
Read 2 more answers
The low temperatures in two cities are being compared. In City 1, the range in temperature is 20°F and the IQR is 7°F. In City 2
Tomtit [17]
I wanna say (C) would be your best bet correct me if I’m wrong
5 0
2 years ago
Read 2 more answers
ANSWER THIS FAST<br> BRANLIEST IS ON THE LINE in
seraphim [82]

Answer:

Option A.) is correct  \triangle XYZ \sim \triangle WVZ  by AA similarity. There are two angles that are congruent given by \angle ZXY = \angle ZWV \hspace{0.2cm}  and\hspace{0.2cm}   \angle ZYX = \angle ZVW.

This is because both pairs represent alternate interior angles formed by lines intersecting two parallel lines.

Step-by-step explanation:

From the given figure we can say that

i) Option A.) is correct  \triangle XYZ \sim \triangle WVZ  by AA similarity. There are two angles that are congruent given by \angle ZXY = \angle ZWV \hspace{0.2cm}  and\hspace{0.2cm}   \angle ZYX = \angle ZVW.

This is because both pairs represent alternate interior angles formed by lines intersecting two parallel lines.

4 0
3 years ago
Find all solutions to x³+3x² − 9x − 27 = 0 by factoring the equation.
SCORPION-xisa [38]

Answer:

The solutions are x=-3,\:x=3

Step-by-step explanation:

To factor this cubic polynomial x^3+3x^2-9x-27 you must:

  • Group the polynomial into two sections

x^3+3x^2-9x-27=\left(x^3+3x^2\right)+\left(-9x-27\right)

  • Factor out -9 from (-9x-27)

(-9x-27)=-9\left(x+3\right)

  • Factor out x^2 from (x^3+3x^2)

(x^3+3x^2)=x^2\left(x+3\right)

x^3+3x^2-9x-27=-9\left(x+3\right)+x^2\left(x+3\right)

  • Factor out common term x+3

-9\left(x+3\right)+x^2\left(x+3\right)=\left(x+3\right)\left(x^2-9\right)

x^3+3x^2-9x-27=\left(x+3\right)\left(x^2-9\right)

  • Factor x^2-9

x^2-9=\left(x+3\right)\left(x-3\right)

x^3+3x^2-9x-27= \left(x+3\right)\left(x+3\right)\left(x-3\right)

x^3+3x^2-9x-27=\left(x+3\right)^2\left(x-3\right)=0

  • Using the Zero Factor Theorem: = 0 if and only if = 0 or = 0

x+3=0, \quad{x=-3}\\x-3=0, \quad{x=3}

The solutions are

x=-3,\:x=3

3 0
2 years ago
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