Question

What is the standard form equation of the line shown below?

Answer 1

Answer:

maybe

$y = \frac{1}{2} x + 0.5$

Answer 2

Answer:

x - 2y = - 1

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Obtain the equation in slope- intercept form

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 3, - 1) and (x₂, y₂ ) = (3, 2) ← 2 points on the line

m = $\frac{2+1}{3+3}$ = $\frac{3}{6}$ = $\frac{1}{2}$

y = $\frac{1}{2}$ x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (3, 2), then

2 = $\frac{3}{2}$ + c ⇒ c = $\frac{1}{2}$

y = $\frac{1}{2}$ x + $\frac{1}{2}$ ← in slope- intercept form

Multiply all terms by 2

2y = x + 1 ( subtract 2y from both sides )

0 = x - 2y + 1 ( subtract 1 from both sides )

- 1 = x - 2y , that is

x - 2y = - 1 ← in standard form