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3 years ago

Find the area. The figure is not drawn to scale.

Mathematics

1 answer:

Natalka [10]3 years ago

6 0

Answer:

1188 in²

Step-by-step explanation:

The area of a parallelogram is the product of its base length and height.

A = bh = (36 in)(33 in) = 1188 in²

You might be interested in

The area of an 14-cm-wide rectangle is 322 cm2. What is its length? The length is cm.

Anika [276]

Answer:

The length of rectangle is 23 cm.

Step-by-step explanation:

DIAGRAM :

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large{14\ cm}}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large{14\ cm}}\put(-0.5,-0.4){\bf}\put(-0.5,3.2){\bf}\put(5.3,-0.4){\bf}\put(5.3,3.2){\bf}\end{picture}$

$\begin{gathered}\end{gathered}$

SOLUTION :

Here's the required formula to find the length of rectangle :

${\longrightarrow{\pmb{\sf{A_{(Rectangle)} = l \times b}}}}$

A = Area
l = length
b = breadth

Substituting all the given values in the formula to find the length of rectangle :

$\begin{gathered}\qquad{\longrightarrow{\sf{A_{(Rectangle)} = l \times b}}}\\\\\qquad{\longrightarrow{\sf{322 = l \times 14}}}\\\\\qquad{\longrightarrow{\sf{322 = 14l}}}\\\\\qquad{\longrightarrow{\sf{l = \dfrac{322}{14}}}}\\\\\qquad{\longrightarrow{\sf{l = \cancel{\dfrac{322}{14}}}}}\\\\\qquad{\longrightarrow{\sf{l = 23 \: cm}}}\\\\\qquad{\star{\underline{\boxed{\sf{ \pink{l = 23 \: cm}}}}}}\end{gathered}$

Hence, the length of rectangle is 23 cm.

$\begin{gathered}\end{gathered}$

LEARN MORE :

$\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}$

$\rule{300}{2.5}$

6 0

2 years ago

Read 2 more answers

123456789101112131415

WARRIOR [948]

The mean is 85.2

Explanation:

Add all the numbers together

98+78+84+75+91=426

Divide the sum by the amount of numbers you added together

426/5= 85.2

7 0

3 years ago

The cost of producing hard drives has three parts: cost of materials, cost of labor, and cost of equipment. To produce x hard dr

LenKa [72]

Let $x$ represent the number of hard drives produced.
The first thing we need to do is convert 10 cents to dollars:
$10cents( \frac{1dollar}{100cents} )=0.1dollar$ . Now, we know that the the cost of materials is 30 dollars and the cost of labor is 0.1 dollars, so the total coast to produce $x$ hard drives will be: $30+0.1=30.1x$ .
Now the only thing left is add the cost of equipment to complete our function:
 $f(x)=30.1x+10000$

We can conclude that the equation that could represent the cost function for making x hard drives is f(x)=30.1x+10,000

3 0

3 years ago

Solve for z −cz+6z=tz+83

Alborosie

Answer: z=83/c - 7 + t

Step-by-step explanation:

6 0

3 years ago

Let $M$, $N$, and $P$ be the midpoints of sides $\overline{TU}$, $\overline{US}$, and $\overline{ST}$ of triangle $STU$, respect

AysviL [449]

Answer:

<NPM + <NZM = 146°

Step-by-step explanation:

Given:

In triangle STU: M, N and P are the midpoints of the line TU, US and ST respectively.

Line UZ is the altitude of the triangle STU

<TSU =71°, <TSU = 36°, <TUS = 73°

From the diagram:

N is the midpoint of line SU and M is the mid point of line UT.

∴ Line NM is parallel to line ST

P is the mid point of line ST and M is the mid point of line UT

∴Line PM is parallel to line SU

N is the mid point of line SU and P is the mid point of line ST

∴Line NP is parallel to line UT

Δ SPN = Δ STU = 36°

<SPN + <NPM + <MPT (Sum of angles in a triangle = 180°)

<UST = <MPT = 71°

36° + <NPM + 71° = 180°

<NPM + 107° = 180°

<NPM= 180°-107°

<NPM= 73°

In ΔSNZ, line SN = line NZ

∴ side SN = side NZ

< NSZ = <NZS = 71°

<MTZ = <MZT = 36°

<NZS + <NZM <MZT = 180° (Sum of angles in a triangle = 180°)

71° + <NZM + 36° = 180°

107° + <NZM = 180°

<NZM = 180° - 107°

<NZM = 73°

<NPM + <NZM =73° + 73°

<NPM + <NZM = 146°

5 0

3 years ago