Answer:
- time = 1second
- maximum height = 16m
Step-by-step explanation:
Given the height of a pumpkin t seconds after it is launched from a catapult modelled by the equation
f(t)=-16t²+32t... (1)
The pumpkin reaches its maximum height when the velocity is zero.
Velocity = {d(f(x)}/dt = -32t+32
Since v = 0m/s (at maximum height)
-32t+32 = 0
-32t = -32
t = -32/-32
t = 1sec
The pumpkin reaches its maximum height after 1second.
Maximum height of the pumpkin is gotten by substituting t = 1sec into equation (1)
f(1) = -16(1)²+32(1)
f(1) = -16+32
f(1) = 16m
The maximum height of the pumpkin is 16m
Answer:
a = 13,
b = 28,
c = 6,
d = 22,
e = 31
Step-by-step explanation:
E = 15 +16 = 31
6 males like cats ( the middle section) so C = 6
d = 6 +16 = 22
a = 19-6 = 13
b = 50-22 = 28
so in order: a = 13, b = 28, c = 6, d = 22, e = 31
The class 4S because you divide each number by its mean mark and standard division and 4S is the highest.
