Answer:
(a) The probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b) The probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Step-by-step explanation:
Let the random variable <em>X</em> follow a Normal distribution with parameters <em>μ</em> = 155.4 and <em>σ</em> = 49.5.
(a)
Compute the probability that a single randomly selected value lies between 158.6 and 159.2 as follows:
*Use a standard normal table.
Thus, the probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b)
A sample of <em>n</em> = 246 is selected.
Compute the probability that a sample mean is between 158.6 and 159.2 as follows:
*Use a standard normal table.
Thus, the probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Answer:
(x-8)(x+7)
Step-by-step explanation:
using quadratic formula we have
x= 
we have:
x^2-x-56=0
a= 1 b=-1 c=-56
so we have:
x=(-(-1)+-sqrt(1^1-4*(1)*(-56)))/(2*1)
x=1+-sqrt(1-4*(-56))/(2)
x=(1+-sqrt(225))/2
x=(1+-15)/2
so we have the roots:
x1=(1+15)/2 =8
x2=(1-15)/2=-7
so the answer is (x-8)(x+7)
1.C
2.C
3.B
4.A
5.D
100% Enjoy :)
Brainliest answer (if Possible)
1) 23
2) -20
3) 2
4) -28
5) -11
Answer:
Step-by-step explanation:
Given that among 500 freshmen pursuing a business degree at a university, 315 are enrolled in an economics course, 213 are enrolled in a mathematics course, and 123 are enrolled in both an economics and a mathematics course.
From the above we find that
a) either economics of Math course is
Out of 500 students 405 have taken either Math or Economics
Hence
c) student who have taken neither = 
Exactly one course is either math or economics - both
= 
