Slope: (y2-y1)/(x2-x1)
Points: (-4,-6), (2,6)
(6+6)/(2+6) = 12/8 = 3/2
Y = 3/2x +b
-6 = 3/2(-4) + b
-6 = -6 + b, b = 0
Equation: y = 3/2x
U/9 = 8/12 u = 6
Step 1: Cancel the common factor (4)
u = 2
—- —-
9 3
Step 2: multiply both sides by 9
9u 2 * 9
—- = ——-
9 3
Step 3: simplify
2 *9 = 18
18 ÷ 3 = 6
u = 6
Answer:
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Step-by-step explanation:
Hope it helps
Answer:
Since 60° is one sixth of the entire circle (360°) it means that the length of arc B is 1/6 th of the circumference.
1/6 * (12 * 2π) = 4π
Answer: Arc CE measures 62 units
Step-by-step explanation: What we have in the question is a circle with two secants ABC and ADE. The two secants have been extended such that two arcs have been formed which are, major arc CE (that is, 4x - 10) and minor arc BD (that is 26).
When you have a circle with two intersecting secants, the angle x (that is angle CAE) is derived as half of the difference of the two intercepted arcs. That is;
Angle x = 1/2 [CE - BD)
Angle x = 1/2 [ (4x - 10) - 26]
Angle x = 1/2(4x - 36)
Cross multiply and we now have
2x = 4x - 36
Collect like terms and we now have
36 = 4x - 2x
36 = 2x
Divide both sides by 2
18 = x
Having calculated x as 18, where arc CE equals 4x - 10, then substitute for the value of x.
CE = 4(18) - 10
CE = 72 - 10
CE = 62
