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Dimas [21]
3 years ago
7

\sqrt[]{2} ) {}^{2} " alt="(3 + \sqrt[]{2} ) {}^{2} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Vesnalui [34]3 years ago
6 0

Answer:

11 + 6\sqrt{2}

Step-by-step explanation:

(3 + \sqrt{2} )²

= (3 + \sqrt{2} )( 3 + \sqrt{2} )

Each term in the second factor is multiplied by each term in the first factor

= 3( 3 + \sqrt{2} ) + \sqrt{2} ( 3 + \sqrt{2} )

Distribute each parenthesis noting that \sqrt{2} × \sqrt{2} = 2

= 9 + 3\sqrt{2} + 3\sqrt{2} + 2 ← collect like terms

= 11 + 6\sqrt{2}

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Solve this system by elimination <br> 10x+6y=14<br> -x-6y=-23
ludmilkaskok [199]

Answer:

(-1, 4)

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define systems</u>

10x + 6y = 14

-x - 6y = -23

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Elimination</em>

  1. Add 2 equations together:                    9x = -9
  2. Divide 9 on both sides:                          x = -1

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define original equation:                    -x - 6y = -23
  2. Substitute in <em>x</em>:                                     -(-1) - 6y = -23
  3. Multiply:                                                1 - 6y = -23
  4. Subtract 1 on both sides:                     -6y = -24
  5. Divide -6 on both sides:                      y = 4
8 0
3 years ago
What ratios are equivalent to each other.
zysi [14]

Answer:

b and d/ a and c

Step-by-step explanation:

6 0
3 years ago
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Point c’(-4,-3) is the same image of C(-2,-3) under a translation
vivado [14]

Answer:

the translation is to the left 2 times

Step-by-step explanation:

-2-2=-4

there is no changes to the y value

6 0
3 years ago
I need help :) please and thank u if u get it right i will give u brainlist
Dvinal [7]

Answer:

4 14/25

Step-by-step explanation:

4.56 = 4 56/100 = 4 14/25

6 0
3 years ago
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Please help me with an addition formula problem!
andrew-mc [135]
2a + 3b = 6
5a + 2b = 4

We multiply the first equation by 5 and the second by 2 and and subtract the second from the first:

10a + 15b = 30
-10a -4b = -8

11b = 22
b = 2

2a + 3(2) = 6
2a = 0
a = 0

Checking,
5(0) + 2(2) = 4
4 = 4, true
6 0
3 years ago
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