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Hunter-Best [27]
3 years ago
11

George places 35 books on 7 shelves each shelf holds the same number of books which equations can be used to find how many books

are on a Shelf
Mathematics
1 answer:
tino4ka555 [31]3 years ago
5 0
35 divided by 7=5 so there's 5 books on each shelf
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What is the measure of EBC?
kramer

Answer:

To measure EBC colour, the light absorption is detected at 430 nm (MEBAK 2.16. 2 respectively EBC 9.4). ... Then the absorption will be measured in a 10mm cuvette. The sample will be diluted until the absorption is less than 2 Extinction units (E430). EBC colour = E430 x 25 x dilution factor.

Step-by-step explanation:

hope this helped

7 0
4 years ago
The heights (in cm) and arm spans (in cm) of 31 students were measured. The association between (height) and (arm span) is shown
sergeinik [125]

Answer: Mike's arm span is 7.165 cm longer than the George's one.

Step-by-step explanation:

We have that the association between height and arm span is modeled by the equation

y = 4.5 + 0.977*x

where y is height and x is arm span.

Mike is 172 cm tall, so his arm span is:

172cm = 4.5 + 0.977*x

x = (172 - 4.5)/0.977 = 171.443 cm

and George is 165 cm tall, so his arm span is:

x = (165 - 4.5)/0.977 = 164.278 cm

Then the difference between their arm span is:

171.443cm - 164.278cm = 7.165 cm

So Mike's arm span is 7.165 cm longer than the George's one.

6 0
3 years ago
MATH.... TRIANGLE JKL HAS VERTICES...
7nadin3 [17]
<h3>Answer: Choice (d)</h3>

Explanation:

To reflect over the y axis, we apply this rule

(x,y) \to (-x,y)

which says to flip the sign of the x term but keep the y coordinate the same.

So that means something like J(-2,5) becomes J ' (2, 5). The other points are handled in the same fashion and that leads us to choice (d). Points on the y axis will stay where they are.

6 0
3 years ago
Maclaurin series of sinx
olga nikolaevna [1]

Answer:

cos(u) and sin(u) can be expanded in with a Maclaurin series, and cos(c) and sin(c) are constants.

Step-by-step explanation:

thats it

7 0
4 years ago
Ray has found that his new car gets 31 miles per gallon on the highwayand 26 miles per gallon in the city. He recently drove 285
Mkey [24]

Answer:

Highway = 155\ miles

City = 130\ miles

Step-by-step explanation:

Given

Highway = 31mi/gallon

City = 26mi/gallon

Total\ Miles = 285

Total\ Gallons = 10

Required

Determine the number of miles driven on the highway and on the city

Represent the gallons used on highway with h and on city with c.

So, we have:

c + h = 10 ---- gallons used

and

31h + 26c = 285 --- distance travelled

In the first equation, make c the subject

c = 10 - h

Substitute 10 - h for c in the second equation

31h + 26c = 285

31h + 26(10 - h) = 285

Open bracket

31h + 260 - 26h = 285

Collect like terms

31h - 26h = 285 - 260

5h = 25

Make h the subject

h = \frac{25}{5}

h = 5

Substitute 5 for h in c = 10 - h

c = 10 - 5

c = 5

If on the highway, he travels 31 miles per gallon, then his distance on the highway is:

Highway = 31 * 5

Highway = 155\ miles

If in the highway, he travels 26 miles per gallon, then his distance on the highway is:

City = 26 * 5

City = 130\ miles

8 0
3 years ago
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