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3 years ago

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What is the perimeter of an equilateral triangle that has a height of 24m?

1 answer:

Nadusha1986 [10]3 years ago

4 0

X root 3 = 24 so x=8 root 3. that's the length of half a side. 16 root 3 is a full side, so the perimeter is 48 root 3.

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Confoosed bab here please help ☹️

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Answer: it should be 565.5

Step-by-step explanation:

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The equation a = StartFraction one-half EndFraction left-parenthesis b 1 plus b 1 right-parenthesis.(b1 + b2)h can be used to de

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Answer:

The equivalent expressions are:

$b1=\frac{2a}{h}-b2$

$h=\frac{2a}{b1+b2}$

Step-by-step explanation:

Given equation for finding area of a trapezoid:

$a=\frac{1}{2}(b1+b2)h\\$

where $a$ represents area, $h$ represents height and $b1\ and\ b2$ represents the base lengths of the trapezoid.

Evaluating $h$ by rearranging the equation to find an equivalent equation.

Multiplying both sides by 2.

$2\times a=2\times\frac{1}{2}(b1+b2)h$

$2a=(b1+b2)h$

Dividing both sides by $b1+b2$

$\frac{2a}{b1+b2}=\frac{(b1+b2)h}{b1+b2}$

$\frac{2a}{b1+b2}=h$

$\therefore h=\frac{2a}{b1+b2}$

Evaluating $b1$ by rearranging the equation to find an equivalent equation.

Multiplying both sides by 2.

$2\times a=2\times\frac{1}{2}(b1+b2)h$

$2a=(b1+b2)h$

Dividing both sides by $h$

$\frac{2a}{h}=\frac{(b1+b2)h}{h}$

$\frac{2a}{h}=b1+b2$

Subtracting both sides by $b2$

$\frac{2a}{h}-b2=b1+b2-b2$

$\frac{2a}{h}-b2=b1$

$\therefore b1=\frac{2a}{h}-b2$

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Charra [1.4K]

As it has been given that $x=4+5i$ , $y=2-9i$ .

We need to find the value of the following:

(i) $4x-y$ , substituting the value of 'x' and 'y' in the expression, we get:

$4(4+5i)-(2-9i)=4\times 4+4\times 5i-2+9i=16+20i-2+9i$

$=14+29i$

So, $4x-y=14+29i$

(ii) $-x+3y$ , substituting the value of 'x' and 'y' in the expression, we get:

$-(4+5i)+3(2-9i)=-4-5i+3\times 2-3 \times 9i=-4-5i+6-27i$

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So, $-x+3y=2-32i$

(iii) $x \times y$ , we need to substitute the value of 'x' and 'y' in the expression, for this, we can use distributive property of multiplication that says,

$a(b+c)=a \times b+ a \times c$

Using the distributive property of multiplication:

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Now, we know that $i \times i=i^2=-1$

We get, $8-36i+10i-45 \times (-1)=8-26i+45$

$=8+45-26i=53-26i$

Therefore, $x \times y$ = $53-26i$ .

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$2(4+5i)\times (2-9i)$

Again, we can use distributive property of multiplication that says,

$a(b+c)=a \times b+ a \times c$

So,

$2(4+5i) \times (2-9i)=2\times 4+2 \times 5i\times(2-9i)$

$=8+10i \times(2-9i)=8\times 2-8 \times 9i+10i \times 2-10i \times 9i$

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since, $i^2=-1$

we get,

$16-72i+20i-90 \times (-1)=16-52i+90$

$=106-52i$

Therefore,

$2x \times y=106-52i$

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