Just multiply across which is
8*5 = 40
21*16 = 336
40/336 = 5/42
This is correct answer
I hope this answer helped you!!! Thank you!!!
Answer:
8 - 2π square units.
π/16 - 1/8 square units.
6π - 9√3 square units.
Step-by-step explanation:
The area of the square = 2√2 * 2√2
= 2*2*2
= 8.
The area of the circle = πr^2
= π * [ ( 2√2)/ 2) ]^2
= π (√2)^2
= 2π.
Second Question:
The area of the circle = π(1/2)^2 = π/4.
Finding the area of the square:
1^2 = 2x^2
x^2 = 1/2
So the area of the square = 1/2
So the area of the red part = 1/4 ( π/4 - 1/2).
= π/16 - 1/8.
Third question
Area of the circle = 6^2 * π = 36π.
Now 60 degrees is 1/6 of 360 degrees so the are of the sector is 6π.
The area of the segment = 6π - 0.5 * 6^2 sin 60
= 6π - 18√3/2
= 6π - 9√3 square units.
Answer:10 hours to read all 250 pages
Step-by-step explanation:
Answer:
The minimum value of the width is 15 ft and the maximum value of the width is 30 ft
Step-by-step explanation:
Let
x -----> the length of the deck
y ----> the width of the deck
we know that
The perimeter of the deck is equal to
so
-----> equation A
The area is equal to
-----> inequality B
Solve the quadratic equation by graphing
The possible width of the deck are the values of y in the interval
[15,30]
All real numbers greater than or equal to 15 ft and less than or equal to 30 ft
see the attached figure
The minimum value of the width is 15 ft and the maximum value of the width is 30 ft
