First, simplify the equation to slope intercept form to find the slope;
2x+3y=4
3y=4-2x
y=(-2x+4)/3
The slopes of parallel lines are the same, therefore, the slope of the second line would also be -2/3
Write out the slope intercept form with the information we know and input the coordinates of the point;
y=mx+c
-4=(-2/3)(1)+c
-4+(2/3)=c
(-12/3)+(2/3)=c
-10/3=c
Therefore, the final equation is y=-2/3x-10/3
Hope I helped :)
Answer:
4,8,12 hope that helps heeeeheheʘ‿ʘ
3,50 degrees hope This heal
Find the intersection point between the 2 restraint equations:
30 - 2x = 12 - \frac{1}{2} x \\ \frac{3}{2} x = 18 \\ x = 12
Substitute back in to find y-value:
y = 30 - 2(12) = 6
P is maximized at point (12,6)
P = 9(12)+9(6) = 162
F is increasing, there are no jumps: if there's a jump from an a to a b
then one of the endpoints would be a limit point of F(S)
