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Rina8888 [55]
3 years ago
6

Five friends bought admission tickets the museum and a box lunch.the cost of each admission ticket was $11.75.each box lunch cos

t $5.write two equivalent expressions and then find the total cost.
Mathematics
1 answer:
slega [8]3 years ago
4 0
Cost of the admission tickets: 11.75x

Cost of the box lunch: 5x

Expressions to find the total cost = (1) ....... 11.75x + 5x

That is equivalent to: (2) .......... (11.75 + 5)x = 16.75x.

Now calculate the cost for x = 5 using both expressions:

1) 11.75(5) + 5(5) = 58.75 + 25 = 83.75

2) 16.75(5) = 83.75

Of course you got the same result with both expressions.
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M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

see graph below

Explanation:

Given:

The image of a quadrilateral on a coordinate plane

To find:

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First, we need to state the coordinates of the original image:

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\begin{gathered} Dilation\text{ rule:} \\ (x,\text{ y\rparen}\rightarrow(kx,\text{ ky\rparen} \\ where\text{ k = scale factor} \\  \\ scale\text{ factor = 1/2} \\ M^{\prime}\text{ = \lparen}\frac{1}{2}(3),\text{ }\frac{1}{2}(-2)) \\ M^{\prime}\text{ = \lparen}\frac{3}{2},\text{ -1\rparen} \\  \\ F\text{ = \lparen}\frac{1}{2}(4),\text{ }\frac{1}{2}(-2)) \\ F^{\prime}\text{ = \lparen2, -1\rparen} \end{gathered}\begin{gathered} L\text{ = \lparen}\frac{1}{2}(1),\text{ }\frac{1}{2}(-5)) \\ L^{\prime}\text{ = \lparen}\frac{1}{2},\text{ }\frac{-5}{2}) \\  \\ W\text{ = \lparen}\frac{1}{2}(5),\text{ }\frac{1}{2}(-5)) \\ W^{\prime}\text{ = \lparen}\frac{5}{2},\text{ }\frac{-5}{2}) \end{gathered}

The new coordinates:

M' (3/2, -1), F' (2, -1), L' (1/2, -5/2), W' (5/2, -5/2)

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

Plotting the coordinates:

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