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2 years ago

6

Five friends bought admission tickets the museum and a box lunch.the cost of each admission ticket was $11.75.each box lunch cos

t $5.write two equivalent expressions and then find the total cost.

1 answer:

slega [8]2 years ago

4 0

Cost of the admission tickets: 11.75x

Cost of the box lunch: 5x

Expressions to find the total cost = (1) ....... 11.75x + 5x

That is equivalent to: (2) .......... (11.75 + 5)x = 16.75x.

Now calculate the cost for x = 5 using both expressions:

1) 11.75(5) + 5(5) = 58.75 + 25 = 83.75

2) 16.75(5) = 83.75

Of course you got the same result with both expressions.

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Resistors for electronic circuits are manufactured on a high-speed automated machine. The machine is set up to produce a large r

Anettt [7]

Answer:

See explanation

Step-by-step explanation:

Given

See attachment for proper presentation of question

Required

Mean and Range

To do this, we simply calculate the mean and the range of each row.

$\bar x = \frac{\sum x}{n}$ ---- mean

Where:

$n = 4$ ---- number of rows

$R = Highest - Lowest$ --- range

So, we have:

Sample 1

$\bar x_1 = \frac{1027+ 994 +977 +994 }{4}$

$\bar x_1 = 998$

$R_1 = 1027- 994$

$R_1 = 33$

Sample 2

$\bar x_2 = \frac{975 +1013 +999 +1017}{4}$

$\bar x_2 = 1001$

$R_2 = 1017 - 975$

$R_2 = 42$

Sample 3

$\bar x_3 = \frac{988 +1016 +974 +997}{4}$

$\bar x_3 = 993.75$

$R_3 = 1016-974$

$R_3 = 42$

Sample 4

$\bar x_4 = \frac{998 +1024 +1006 +1010}{4}$

$\bar x_4 = 1009.5$

$R_4 = 1024 -998$

$R_4 = 26$

Sample 5

$\bar x_5 = \frac{990 +1012 +990 +1000}{4}$

$\bar x_5 = 998$

$R_5 = 1012 -990$

$R_5 = 22$

Sample 6

$\bar x_6= \frac{1016 + 998 +1001 +1030}{4}$

$\bar x_6= 1011.25$

$R_6= 1030-998$

$R_6= 32$

Sample 7

$\bar x_7 = \frac{1000 +983 +979 +971}{4}$

$\bar x_7 = 983.25$

$R_7 = 1000-971$

$R_7 = 29$

Sample 8

$\bar x_8 = \frac{973 +982 +975 +1030}{4}$

$\bar x_8 = 990$

$R_8 = 1030-973$

$R_8 = 57$

Sample 9

$\bar x_9 = \frac{992 +1028 +991 +998}{4}$

$\bar x_9 = 1002.25$

$R_9 = 1028 -991$

$R_9 = 37$

Sample 10

$\bar x_{10} = \frac{997 +1026 +972 +1021}{4}$

$\bar x_{10} = 1004$

$R_{10} = 1026 -972$

$R_{10} = 54$

Sample 11

$\bar x_{11} = \frac{990 +1021 +1028 +992}{4}$

$\bar x_{11} = 1007.75$

$R_{11} = 1028 -990$

$R_{11} = 38$

Sample 12

$\bar x_{12} = \frac{1021 +998 +996 +970}{4}$

$\bar x_{12} = 996.25$

$R_{12} = 1021 -970$

$R_{12} = 51$

Sample 13

$\bar x_{13} = \frac{1027 +993 +996 +996}{4}$

$\bar x_{13} = 1003$

$R_{13} =1027 -993$

$R_{13} =34$

Sample 14

$\bar x_{14} = \frac{1022 +981 +1014 +983}{4}$

$\bar x_{14} = 1000$

$R_{14} = 1022 -981$

$R_{14} = 41$

Sample 15

$\bar x_{15} = \frac{977 +993 +986 +983}{4}$

$\bar x_{15} = 984.75$

$R_{15} = 993-977$

$R_{15} = 16$

8 0

2 years ago

If 111 people attend a concert and tickets for adults cost $4 while tickets for children cost $3.25 and total receipts for the c

VikaD [51]

Answer:

57 children

54 adults

Step-by-step explanation:

Let's call x the number of children admitted and call z the number of adults admitted.

Then we know that:

$x + z = 111$

We also know that:

$3.25x + 4z = 401.25$

We want to find the value of x and z. Then we solve the system of equations:

-Multiplay the first equation by -4 and add it to the second equation:

$-4x - 4z = -444$

$3.25x + 4z = 401.25$

----------------------------------

$-0.75x = -42.75$

$x =\frac{-42.75}{-0.75}\\\\x=57$

Now we substitute the value of x in the first equation and solve for the variable z

$57 + z = 111$

$z = 111-57$

$z = 54$

5 0

2 years ago

Read 2 more answers

Josiah and his friends are going to the movies. Each ticket costs $10, and popcorn is $5 a bag. There is a $3 service fee for th

Free_Kalibri [48]

Make sure you check this because i do make mistakes.

10 x 4 = 40

75 - 40 = 35

So josiah has 35 dollars to spend for things other than tickets.

35 - 3 = 32 (for the service fee)

So josiah has 32 dollars to spend on popcorn

32/5 = 6.4 but you cant have half a bag of popcorn so

6 bags

8 0

2 years ago

Factor<br> 3M^2+11MN+6N^2

antoniya [11.8K]

3M^2 + 11MN + 6N^2 = 3M^2 + 2MN + 9MN + 6N^2

= M(3M + 2N) + 3N(3M + 2N) = (3M + 2N)(M + 3N)

Answer: 3M^2 + 11MN + 6N^2 = (3M + 2N)(M + 3N)

8 0

2 years ago

3V3<br> х<br> 60°<br> Find the values of x and y. Write your answers in simplest form.<br> X=<br> y=

Alex787 [66]

Answer:

X=3

y=6

Step-by-step explanation:

$tan60=\sqrt{3}=\frac{3\sqrt{3} }{x} \\\\x=3$

-----------

$sin60=\frac{\sqrt{3} }{2} =\frac{3\sqrt{3} }{y} \\\\y=6$

hope it helps...

have a great day!!

6 0

2 years ago