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Rina8888 [55]
3 years ago
6

Five friends bought admission tickets the museum and a box lunch.the cost of each admission ticket was $11.75.each box lunch cos

t $5.write two equivalent expressions and then find the total cost.
Mathematics
1 answer:
slega [8]3 years ago
4 0
Cost of the admission tickets: 11.75x

Cost of the box lunch: 5x

Expressions to find the total cost = (1) ....... 11.75x + 5x

That is equivalent to: (2) .......... (11.75 + 5)x = 16.75x.

Now calculate the cost for x = 5 using both expressions:

1) 11.75(5) + 5(5) = 58.75 + 25 = 83.75

2) 16.75(5) = 83.75

Of course you got the same result with both expressions.
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Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

Let h bet the # of hours worked

If Cynthia earns $13 per hour then her equation would be:

C = $13h

If Amy makes $1.5 more per hour then her equation would be:

A = $14.5x

Now lets plug in some numbers:)

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A = $630.75

7 0
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Tanzania [10]

Recall that

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Dividing both sides by cosh²(x) gives

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Also, recall the identity

\sinh(2x) = 2\sinh(x)\cosh(x)

Then

\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \dfrac{2\tanh\left(\frac x2\right)}{\mathrm{sech}^2\left(\frac x2\right)} \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\tanh\left(\dfrac x2\right)\cosh^2\left(\dfrac x2\right) \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\sinh\left(\dfrac x2\right)\cosh\left(\dfrac x2\right) \\\\\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \sinh(x)

4 0
3 years ago
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Answer:

(x-3)(x^2-7) = x^3 -3x^2 -7x + 21

just change the sign of the root and put x in front of it, then multiply the factors all together

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(x-sqr7)(x+sqr7) = x^2-7.  similar to (a-b)(a+b) = a^2-b^2

Step-by-step explanation:

6 0
3 years ago
I = prt
lukranit [14]

Step-by-step explanation:

S.I = PRT

=$7430×(5÷100)× 3

=$1114•50

5 0
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