X - 1 < = 9         or         2x > = 24
x < = 9 + 1                    x > = 24/2
x < = 10                        x > = 12
closed circle on 10, shaded to the left
closed circle on 12, shaded to the right
________10_______12__________
       <====X                 X======>
the X represents closed circles
        
             
        
        
        
Answer:
The points for the given to linear equations is (5 , - 2) and (5 , - 1)
The points is plotted on the graph shown . 
Step-by-step explanation:
Given as :
The two linear equation are
y =  x - 1                  ...........1
x - 1                  ...........1
y =  x - 6                  ...........2
x - 6                  ...........2
Now, Solving both the linear equations
Put the value of y from eq 2 into eq 1
I.e   x - 6 =
x - 6 =  x - 1
x - 1 
Or,  x +
x +  x  = 6 - 1
x  = 6 - 1 
Or,   x = 5
x = 5
or,  x = 5
x = 5
∴ x = 5
Now, Put the value of x in eq 1
So, y =  x - 1
x - 1      
Or, y =  × 5 - 1
× 5 - 1               
or,  y =  - 1
 - 1
Or, y = - 1 - 1
I.e y = -2
So, For x = 5 , y = - 2
Point is ( ,
 ,  ) = (5 , - 2)
) = (5 , - 2)
 Again , put the value of x in eq 2
So, y =  x - 6
x - 6
Or, y =  × 5 - 6
× 5 - 6
Or, y =  - 6
 - 6
Or, y = 4 - 6
I.e y = - 2
So, For x = 5 , y = - 2
Point is ( ,
 ,  ) = (5 , - 2)
) = (5 , - 2)
Hence, The points for the given to linear equations is (5 , - 2) and (5 , - 2)
The points is plotted on the graph shown . Answer
 
        
             
        
        
        
64=-4+4x
64+4=4x
68=4x
68/4=x
17=x
        
             
        
        
        
Y=Acos(p)+m, A=amplitude, p=period, m=midline, in this case:
A=1/2, p=360(t/12)=30t, m=(10-9)/2+9=9.5 so
h(t)=(1/2)cos(30t)+9.5
        
                    
             
        
        
        
Answer:
The slope is -2/3.
Step-by-step explanation
Let m represent the slope.
m= rise/run= y2-y1/x2-x1
-1 - (-3)/0-3
2/-3
-2/3