I'm assuming you don't still need these? Sorry I didn't see this in time
Dont say you can't! I believe in youu!
The bits are determined by repeated division by 2 to yield either 0 or 1.
183/2 = 91 rem 1 => 1 (lowest bit) 2⁰
91/2 = 45 rem 1 => 1 (next higher bit) 2¹
45/2 = 22 rem 1 => 1 (next higher bit) 2²
22/2 = 11 rem 0 => 0 (next highrt bit) 2³
11/2 = 5 rem 1 => 1 (next higher bit) 2⁴
5/2 = 2 rem 1 => 1 (next higher bit) 2⁵
2/2 = 1 rem 0 => 0 (next higher bit) 2⁶
1/2 = 0 rem 1 => 1 (next higher bit) 2⁷
The next higher 24 bits have 0 in each bit.
For 32-bit system,
183 = 00000000 00000000 00000000 10110111 (with a space between bytes for readability)
Answer: 00000000000000000000000010110111
