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maw [93]
3 years ago
10

Convert the decimal number 183 into an equivalent 32 bit binary number. show all your work.

Mathematics
1 answer:
german3 years ago
7 0
The bits are determined by repeated division by 2 to yield either 0 or 1.
 
183/2 = 91 rem 1  =>  1  (lowest bit)             2⁰
  91/2 = 45 rem 1  =>  1 (next higher bit)     2¹
  45/2 = 22 rem 1 => 1  (next higher bit)     2²
  22/2 = 11 rem 0  => 0 (next highrt bit)      2³
    11/2 = 5 rem 1    => 1 (next higher bit)     2⁴
     5/2 = 2 rem 1   => 1 (next higher bit)     2⁵
     2/2 = 1 rem 0   => 0 (next higher bit)    2⁶
     1/2 = 0 rem 1   => 1 (next higher bit)      2⁷
The next higher 24 bits have 0 in each bit.

For 32-bit system,
183 = 00000000 00000000 00000000 10110111 (with a space between bytes for readability)

Answer: 00000000000000000000000010110111

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explain step by step how to solve. please point out any similarities in the steps used for each question
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#1
m∠A=180 - 115 - 24 = 41°

By the law of sines:

b/sinB = a/sinA  ⇒  
b = (a*sinB)/sinA = (21*sin24°)/sin41° = (21*0.4067)/0.656 ≈ 13

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#2
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By the law of sines:

b/sinB = a/sinA  ⇒  
b = (a*sinB)/sinA = (13*sin119°)/sin27° = (13*0.8746)/0.454 ≈ 25

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#3
m∠C=180 - 57 - 37 = 86°

By the law of sines:

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