Answer:
(Add one then subtract one)
Step-by-step explanation:
I assume you're asked to solve
4 cos²(<em>x</em>) - 7 cos(<em>x</em>) + 3 = 0
Factor the left side:
(4 cos(<em>x</em>) - 3) (cos(<em>x</em>) - 1) = 0
Then either
4 cos(<em>x</em>) - 3 = 0 <u>or</u> cos(<em>x</em>) - 1 = 0
cos(<em>x</em>) = 3/4 <u>or</u> cos(<em>x</em>) = 1
From the first case, we get
<em>x</em> = cos⁻¹(3/4) + 2<em>nπ</em> <u>or</u> <em>x</em> = -cos⁻¹(3/4) + 2<em>nπ</em>
and from the second,
<em>x</em> = <em>nπ</em>
where <em>n</em> is any integer.
The exponential function
f(x) = a^x
can pass through all points as long as x is any real number
As an example, we can choose values of x.
x = -4, x = 0, x=100
The value of the function in terms of a would be
f(-4) = a^-4
f(0) = a^0 = 1
f(100) = a^100
Let the less expensive scarf be x
expensive scarf = $3 + x
According To The Question,
x+x+$3=$25
2x+$3=25
2x=22
x=$11
expensive scarf = x + $3 = $11 + $3 = $14
HOPE THIS WILL HELP YOU
