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Nata [24]
3 years ago
8

What is the effect of reducing friction on a machine?

Physics
2 answers:
spayn [35]3 years ago
8 0
Sometimes  it increases  the efficiency  of the machine.
Reducing   the friction  between the  tires and the ground on a car  will  decrease the  efficiency -- you will  get more wheel slip.   Or reducing the friction between the steel wheels and the rail   on a train will   reduce the efficiency...<span />
il63 [147K]3 years ago
7 0
It increases efficiency. Hope this helps!!!
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Explain in detail what information can be learn about atoms of different elements by examining the periodic table . For the Maxi
raketka [301]

Answer:

We know the information about atomic size, energy, electronic configuration etc. of atom from the periodic table.    

Explanation:

  • Periodic table is the arrangement of elements that are arranged according to their properties and electronic configuration.
  • In periodic table, on furthest right side of the periodic table, noble gases like He, Ne, Ar etc are arranged.
  • The atomic number of element increases while moving from left towards right in the periodic table.
  • The metallic character of element decreases as we proceed the table towards right.
  • They readily accept electron to fill the valence shell hence becoming more metallic in character.  
5 0
3 years ago
A student finds an unlabeled liquid container in his lab. He notices that the container has two liquids. Since the two liquids h
raketka [301]

Answer:

\rho = 1848.03 kg m^{-3}

Explanation:

given data:

density of water \rho = 1 gm/cm^3 = 1000 kg/m^3

height  of water  = 20 cm  =0.2 m

Pressure  p = 1.01300*10^5 Pa

pressure at bottom

P =  P_{fluid} + P_{h_2 o}

P   = P_{fluid}  + \rho g h

P_{fluid}  = P - \rho g h

                 = 1.01300*10^5 - 1000*0.2*9.8

                 = 99340 Pa

p_{fluid}  = P_{atm} + \rho g h_{fluid}                       h_[fluid} = 0.307m

99340 = 104900 + \rho *9.8*0.307

\rho = 1848.03 kg m^{-3}

5 0
4 years ago
What is the momentum of an object with a mass of 60 kg and velocity of 10 m/s?<br><br> heeelp
Pavlova-9 [17]

Answer:

Linear momentum= Mass*Velocity

P=mv

P=60*10

P=600Kg m/s

3 0
3 years ago
- How long does it take a packet of length 1,000 bytes to propagate over a link of distance 2,500 km, propagation speed 2.5 *10^
Sunny_sXe [5.5K]

Answer:

It will take 0.01 s or 10 ms

Solution:

As per the question:

Length of the packet, L = 1,000 bytes = 1000\times 8 = 8000 bits

Distance, d = 2500 km = 2.5\times 10^{6}\ m

Speed of propagation, s = 2.5\times 10^{8}\ m/s

Transmission rate, R = 2 Mbps

Now,

Propagation time, t can be calculated as:

t = \frac{d}{s} = \frac{2.5\times 10^{6}}{2.5\times 10^{8}} = 0.01\ s

t = 10 ms

  • In general, propagation time, t is given by:

       t = \frac{link\ distance}{Propagation\ speed}

  • No, this delay is independent of the length of the packet.
  • No, this delay is independent of the rate of transmission.

3 0
4 years ago
Does calm water have a regular reflection or a diffuse reflection
Shtirlitz [24]
A regular relflection
8 0
3 years ago
Read 2 more answers
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