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butalik [34]
3 years ago
11

A student finds an unlabeled liquid container in his lab. He notices that the container has two liquids. Since the two liquids h

ave different density, there is a distinct separation between them. Water, which has a density of 1.00g/cm^3, fills the lower portion of the container to a depth of 20.0 cm.The fluid which is floating on top of the water is 30.7 cm deep. If the absolute pressure on the bottom of the container is 104900 Pa, what is the density ???? of the unknown fluid? The acceleration due to gravity is g=9.81 m/s^2 and atmospheric pressure is P0=101300 Pa.
Physics
1 answer:
raketka [301]3 years ago
5 0

Answer:

\rho = 1848.03 kg m^{-3}

Explanation:

given data:

density of water \rho = 1 gm/cm^3 = 1000 kg/m^3

height  of water  = 20 cm  =0.2 m

Pressure  p = 1.01300*10^5 Pa

pressure at bottom

P =  P_{fluid} + P_{h_2 o}

P   = P_{fluid}  + \rho g h

P_{fluid}  = P - \rho g h

                 = 1.01300*10^5 - 1000*0.2*9.8

                 = 99340 Pa

p_{fluid}  = P_{atm} + \rho g h_{fluid}                       h_[fluid} = 0.307m

99340 = 104900 + \rho *9.8*0.307

\rho = 1848.03 kg m^{-3}

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Yakvenalex [24]

Answer:

Step one : read the directions

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Explanation:

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2 years ago
14. If the spring constant of a simple harmonic oscillator is doubled, by what factor will the mass of the system need to change
klio [65]

Lets se

And

\\ \rm\Rrightarrow T=2\pi\sqrt{\dfrac{m}{k}}

\\ \rm\Rrightarrow \sqrt{k}T=2\pi\sqrt{m}

So

\\ \rm\Rrightarrow k\propto m

If spring constant is doubled mass must be doubled

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2 years ago
Which of the following is the best thermal insulator?
Vera_Pavlovna [14]

B. Aluminum is possibly correct

4 0
3 years ago
A block of mass 27.00 kg sits on a horizontal surface with, coefficient of kinetic
zhannawk [14.2K]

Answer:

The force is  F  = 172 \ N

Explanation:

From the question we are told that

    The  mass of the block is  m_b  = 27.0 \ kg

     The  coefficient of  static friction is  \mu_s  =  0.65

     The coefficient of kinetic friction is  \mu_k  =  0.50

The  normal force acting on the block is  

      N  =  m *  g

substituting values

     N  =   27 *  9.8

     N  =   294.6  \  N

Given that the force we are to find is the force required to get the block to start moving then the force acting against this force is the static frictional force which is mathematically evaluated as

        F_f  =  \mu_s  *  N

substituting values

        F_f  =   0.65 *  264.6

        F_f  =   172 \ N

Now for this  block to move the force require is  equal to F_f i.e

       F= F_f

=>    F  = 172 \ N

       

   

5 0
3 years ago
A small sphere with mass m is attached to a massless rod of length L that is pivoted at the top, forming a simple pendulum. The
USPshnik [31]

Answer:

a) see attached, a = g sin θ

b)

c)   v = √(2gL (1-cos θ))

Explanation:

In the attached we can see the forces on the sphere, which are the attention of the bar that is perpendicular to the movement and the weight of the sphere that is vertical at all times. To solve this problem, a reference system is created with one axis parallel to the bar and the other perpendicular to the rod, the weight of decomposing in this reference system and the linear acceleration is given by

          Wₓ = m a

          W sin θ = m a

          a = g sin θ

b) The diagram is the same, the only thing that changes is the angle that is less

                θ' = 9/2  θ

             

c) At this point the weight and the force of the bar are in the same line of action, so that at linear acceleration it is zero, even when the pendulum has velocity v, so it follows its path.

The easiest way to find linear speed is to use conservation of energy

Highest point

            Em₀ = mg h = mg L (1-cos tea)

Lowest point

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          Em₀ = Emf

          g L (1-cos θ) = v² / 2

              v = √(2gL (1-cos θ))

4 0
3 years ago
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