To find the relative frequencies, divide each frequency by the total number of throws - in this case, 100.
Red: 10/100=1/10=0.1
Yellow:35/100=0.35
Blue:48/100= 0.48
Misses: 7/100=0.07
The event of landing in the red region has a relative frequency of 0.1 which means the dart landed in the red region about 10% (0.1 x 100%) of the time.
Answer:
Here we do not have the vector, but I will try to give a kinda general solution to this type of problem.
If the vector is written as (a, b, c) we have that the force in the x-axis is of a Newtons, in the y-axis is of b Newtons, and in the z-axis is of c Newtons.
Then, we can calculate the total magnitude of this force as:
F = √( a^2 + b^2 + c^2)
wich gives us the total magnitude of the force, but not a direction or anything like that, this is just a scalar.
<span>For the answer to the question above.
The pressure (the symbol "P") is the force per unit area applied in a direction perpendicular to the surface of an object.
This is from least to greatest: 0.3Pa, 16 N/m2, 311 N.m2, 4kPa</span>
A drop in temperature would most likely result in a decline in the rate of energy production in a fusion nuclear reactor.
<h3>What is nuclear power?</h3>
The utilization of nuclear reactions to generate energy is known as nuclear power.
Nuclear power facilities produce the great bulk of the electricity generated by nuclear fission of uranium and plutonium.
The environment should be hot enough for the deuterium and tritium ions' kinetic energies to be sufficient to break through the Coulomb barrier and fuse together.
Therefore, a decrease in temperature would most likely cause a decrease in the rate of energy production in a fusion nuclear reactor.
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Low-energy light bulbs also save money in the long run.
<h3>Mathematical operations</h3>
Cost of 1 low-energy bulb = 400 P
Cost of 1 filament buld = 50 P
Cost of electricity for 1 hour for low-energy bulbs = 0.2 p
Cost of electricity for 1 hour for filament bulb = 1.0 p
Total cost of electricity for 10,000 hours for low-energy bulb:
10,000 x 0.2 p = 2,000 p
Total cost of electricity for 10,000 hours for filament bulb:
10,000 x 1.0 = 10,000 p
Total cost of low-energy bulb + electricity = 2,000 + 400
= 2,400 p
Total cost of filament bulb + electricity = 10,000 + 50
= 10, 050 p
Thus, low-energy bulbs may have an initial higher cost, but they save a significant amount of money in the long run.
More on energy-saving bulbs can be found here:brainly.com/question/13144449
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