Answer:
805.48N/m
Explanation:
According to Hookes law
F = Ke
F is the force = mg
F = 2.4×9.8 = 23.52N
e is the extension = 2.92cm = 0.0292m
Force constant K = F/e
K = 23.52/0.0292
K = 805.48N/m
Hence the force constant of the spring is 805.48N/m
Answer:
he fall movement we see that both the force is different from zero, and the torque is different from zero.
When analyzing the statements the d is true
Explanation:
Let's pose the solution of this problem, to be able to analyze the firm affirmations.
When the person is falling, the weight acts on them all the time, initially the rope has no force, but at the moment it begins to lash it exerts a force towards the top that is proportional to the lengthening of the rope.
The equation for this part is
Fe - W = m a
k x - mg = m a
As the axis of rotation is located at the top where they jump, there is a torque.
What is it
Fe y - W y = I α
angular and linear acceleration are related
a = α r
Fe y - W y = I a / r
In the fall movement we see that both the force is different from zero, and the torque is different from zero.
When analyzing the statements the d is true
Answer: Physical
Explanation: There are no changes being done to the salt. Think of it this way, if you dissolve the salt in water then boil the water completely, you will have the same salt you started with.
Answer:
B and C!
Explanation:
I just did it on edge. I hope this helps!
