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victus00 [196]
3 years ago
9

Each rhino costs 1,000 dollars how much will the farmer loose if all 350 rhinos are stolen

Mathematics
2 answers:
ICE Princess25 [194]3 years ago
6 0

He would lose 350,000 dollars or -350,000.

REY [17]3 years ago
4 0

He would lose 350,000 dollars or -350,000.

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A standard deck of cards has 52 cards, 4 of each type (Ace, King, Queen, Jack, 10,...,2). From a well-shuffled deck, you are dea
Wewaii [24]

Answer:

a)%85,5

b)%92,2

Step-by-step explanation:

a) To determine the probability of getting a hand with at least one face, we need to calculate the probability of the hand without any face firstly.

(36/52)*(35/51)*(34/50)*(33/49)*(32/48)=0,145

Then, we need to deduct this value from the probability 1

1-0,145=0,855

The probability of the hand with at least one face is %85,5.

b)To determine the probability of a hand with at least one ace and face we will track the same road again.

(32/52)*(31/51)*(30/50)*(29/49)*(28/48)=0,0775

Then, we need to deduct this value from the probability 1

1-0,0775=0,922

The probability of the hand with at least one ace and one face is %92,2.

3 0
3 years ago
In a right triangle, if a = 8 and c = 17, what is the correct setup to find the value of b?
salantis [7]

Answer:

b =15

Step-by-step explanation:

We can use Pythagoras theorem to find b:

a^{2}+b^{2} = c^{2}

8^{2} + b^{2} = 17^{2}

64 + b^{2} = 289

64 + 225 = 289

64 + 15^{2} = 289

b = 15

hope this helps :) and sorry if not right

7 0
2 years ago
Read 2 more answers
A farmer feeds her 4 horses 2 bales of hay. How many bales of hay would the farmer need in order to feed 20 horses?
xxMikexx [17]

Answer: 40 bales of hay

Step-by-step explanation:

5 0
3 years ago
Need the answer ASAP
Evgesh-ka [11]
Anwser:

22.5 or 5/22 or 30

Step-by-step Explanation:

-2 and -2
SSS
-2+-2= -4

-4 x 30= -120

-120 divided by 4 is 30
but that’s not a fraction so you do

22.5 or 5/22

-2 x -2 x 30=

7 0
3 years ago
Joe sold a total of 10 baked goods. Each cookie costs $1.25 and each brownie costs $2.50. Joe made $20 at the bake sale. How man
AURORKA [14]

Answer:

4 cookies

Step-by-step explanation:

Let the number of cookies he sold be c and that of brownies be b.

Assuming that brownies and cookies are the only type of baked goods sold,

b +c= 10 -----(1)

Amount of money received= $20

b(cost of brownie) +c(cost of cookie)= $20

2.50b +1.25c= 20 -----(2)

From (1): b= 10 -c -----(3)

Substitute (3) into (2):

2.50(10 -c) +1.25c= 20

Expand:

2.50(10) +2.50(-c) +1.25c= 20

25 -2.50c +1.25c= 20

-1.25c +25= 20

Being constants to 1 side:

-1.25c= 20 -25

-1.25c= -5

c= -5 ÷(-1.25)

c= 4

Thus, Joe sold 4 cookies.

8 0
2 years ago
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