All categories

3 years ago

If the Weight of Candy Is proportional to the price and 12 ounces of candy is $3.00,dollars how much is 20 ounces of candy?

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

4 0

Answer:

$5.00

Step-by-step explanation:

if you divide $3.00 by 12 you get $0.25 which is what your paying per ounce so all you would have to do once you get how much your paying per ounce is multiply your per ounce number ($0.25) by your total amount of ounces (20) and you then get your answer $5.00. Hope this makes sense!

You might be interested in

How to turn 3x = -2y into standard form

zimovet [89]

3x = -2y
or 3x + 2y = 0

it is the standard form.

8 0

3 years ago

Eight less than five times a number is fewer than twenty-four

Hoochie [10]

The clear answer according to me would be

5a-8<24

8 0

3 years ago

Explain why it is important to line up decimal points when you are adding and subtracting decimals. Use the problem 6.32 – 0.5 i

Mazyrski [523]

Answer:

Kindly check explanation

Step-by-step explanation:

When performing addition and subtraction of decimals, it is important to arrange the numbers being added or subtracted such that the decimal points are in line. This is particularly important so that the place value of the numbers are in accord.

To simplify, when then decimals are in line, then the tenth value of the first number will be added to the tenth value of the second. Without this arrangement, one might be adding the hundredth placed value to the tenth or unit value which is mathematically incorrect and will yield a wrong result.

For instance :

6.32 - 0.5

Here, when the decimal point of each number is in line, the tenth placed value of the first number (3) matches the tenth placed number of the second number (5) and all others also fall in place automatically.

____6.32

- ___0.5

________

___ 5.82

________

4 0

3 years ago

If a linear system has no solution, what happens when you try to solve the system by adding or subtracting?

balandron [24]

If a system has no solution, it is said to be inconsistent . The graphs of the lines do not intersect, so the graphs are parallel and there is no solution.

3 0

3 years ago

Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are locat

zavuch27 [327]

Answer:

The equation contains exact roots at x = -4 and x = -1.

See attached image for the graph.

Step-by-step explanation:

We start by noticing that the expression on the left of the equal sign is a quadratic with leading term $x^2$ , which means that its graph shows branches going up. Therefore:

1) if its vertex is ON the x axis, there would be one solution (root) to the equation.

2) if its vertex is below the x-axis, it is forced to cross it at two locations, giving then two real solutions (roots) to the equation.

3) if its vertex is above the x-axis, it will not have real solutions (roots) but only non-real ones.

So we proceed to examine the vertex's location, which is also a great way to decide on which set of points to use in order to plot its graph efficiently:

We recall that the x-position of the vertex for a quadratic function of the form $f(x)=ax^2+bx+c$ is given by the expression: $x_v=\frac{-b}{2a}$

Since in our case $a=1$ and $b=5$ , we get that the x-position of the vertex is: $x_v=\frac{-b}{2a} \\x_v=\frac{-5}{2(1)}\\x_v=-\frac{5}{2}$

Now we can find the y-value of the vertex by evaluating this quadratic expression for x = -5/2:

$y_v=f(-\frac{5}{2})\\y_v=(-\frac{5}{2} )^2+5(-\frac{5}{2} )+4\\y_v=\frac{25}{4} -\frac{25}{2} +4\\\\y_v=\frac{25}{4} -\frac{50}{4}+\frac{16}{4} \\y_v=-\frac{9}{4}$

This is a negative value, which points us to the case in which there must be two real solutions to the equation (two x-axis crossings of the parabola's branches).

We can now continue plotting different parabola's points, by selecting x-values to the right and to the left of the $x_v=-\frac{5}{2}$ . Like for example x = -2 and x = -1 (moving towards the right) , and x = -3 and x = -4 (moving towards the left.

When evaluating the function at these points, we notice that two of them render zero (which indicates they are the actual roots of the equation):

$f(-1) = (-1)^2+5(-1)+4= 1-5+4 = 0\\f(-4)=(-4)^2+5(-4)_4=16-20+4=0$

The actual graph we can complete with this info is shown in the image attached, where the actual roots (x-axis crossings) are pictured in red.

Then, the two roots are: x = -1 and x = -4.

5 0

3 years ago