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Sophie [7]
3 years ago
5

Write the slope -intercept form of an equation of the line that passes through the given point and is parallel to the graph of t

he equation.
5,-5,3x+y=-2

A. y=10x+3
B. y=-3x+10
C. y=1/3x-10
D. y=-3x-10
Mathematics
1 answer:
ElenaW [278]3 years ago
7 0

Answer:

The equation of the required line in the slope-intercept form is

y = -3x + 10

Step-by-step explanation:

i) the required line passes through the point (5, -5)

ii) the required line is also parallel to the line 3x + y = -2 ⇒ y = -3x - 2

  Therefore the slope of the given line is -3.

  Therefore the slope of the required line is also -3

  The equation of the required line in the slope-intercept form is

  y - (-5) = -3(x - 5) ⇒ y + 5 = -3x + 15    ⇒      y = -3x + 10   ∴ 3x + y = 10.

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6 0
3 years ago
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Dahasolnce [82]

Answer:

8 + k² - 6 > 8(k + 2) - 4k when k = 7

Step-by-step explanation:

8 + k² - 6 = 8 + 7² - 6 = 51

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8 0
3 years ago
[2.03] Solve: 4(x + 1) = 4x + 4<br><br> No Solution<br><br> 0<br><br> Any Real Number<br><br> 1
vampirchik [111]
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7 0
3 years ago
Read 2 more answers
Find the area of the rhombus. d1 = 14 m; d2 = 18 m The area of the rhombus is ? m2.
xxTIMURxx [149]

<u><em>Answer:</em></u>

Area of rhombus = 126 m²

<u><em>Explanation:</em></u>

<u>We are given that the two diagonals of the rhombus are:</u>

D₁ = 14 meters and D₂ = 18 meters

<u>The area of the rhombus using its diagonals can be calculated using the following rule:</u>

Area = \frac{D_1 * D_2}{2}

<u>Substitute with the given values to get the area as follows:</u>

Area = \frac{14*18}{2}=126 m^2

Hope this helps :)

8 0
3 years ago
Read 2 more answers
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