Answer:
A 0.24 probability that one string is defective
Step-by-step explanation:
The sample probabiity:


If important to notice that this probability is from the sample, it can be extrapolated to the population but may not be the same.
Answer: The number of different combinations of 2 vegetables are possible = 15 .
Step-by-step explanation:
In Mathematics , the number of combinations of selecting r values out of n values = 
Given : Number of available vegetables = 6
Then, the number of different combinations of 2 vegetables are possible will be :

Hence , the number of different combinations of 2 vegetables are possible = 15 .
Answer:
DF = 14
Step-by-step explanation:
Andrew was wrong in the assumption that DE = EF
Segments of tangents to a circle from the same external point are congruent
That is
EF = FG = 8
Then
DF = DE + EF = 6 + 8 = 14
Answer:
Step-by-step explanation:
Perimeter is 70 m
so w + w + 6w + 6w = 70
w = 70/14 = 5, l = 30m.
Area = l * w = 30 * 5 = 150 sq m
9514 1404 393
Answer:
x = 0
Step-by-step explanation:
You can eliminate parentheses and subtract 50.
5(2x +10) = 50
10x +50 = 50 . . . . use the distributive property
10x = 0 . . . . . . . . . subtract 50 from both sides
x = 0 . . . . . . . . . . . divide by 10
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<em>Check</em>
5(2·0 +10) = 50
5(10) = 50 . . . . true