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boyakko [2]
3 years ago
13

Line AB contains points A (3, −2) and B (1, 8). The slope of line AB is −5 negative 1 over 5 1 over 5 5

Mathematics
2 answers:
pentagon [3]3 years ago
8 0
Slope = (8+2)/(1 - 3) = 10/-2 = -5
answer
<span> −5 </span>
oee [108]3 years ago
7 0

Answer: -5

Step-by-step explanation:

The slope of a line passing through (a,b) and (c,d) is given by :-

\text{Slope}=\dfrac{d-b}{c-a}

Then the slope of the line AB contains points A (3, −2) and B (1, 8) will be :-

\text{Slope}=\dfrac{8-(-2)}{1-(3)}\\\\\Rightarrow\text{Slope}=\dfrac{10}{-2}-5

Hence, the slope of the line AB contains points A (3, −2) and B (1, 8) = -5

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h(-3) - h( - 2) = -  \frac{5}{  8} \\ \\

Step-by-step explanation:

\boxed{h(x) =  \frac{2 {x}^{2}  - x + 1}{3x - 2}}

h(2) =  \frac{2 {(2)}^{2}  - (2) + 1}{3(2) - 2}

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h( - 3) =  \frac{2 {( - 3)}^{2}  - ( - 3) + 1}{3( - 3) - 2} \\ h( - 3) =  \frac{2 (9) + 3 + 1}{ - 9- 2} \\ h( - 3) =  \frac{18 + 4}{ - 11} \\ h( - 3) =    \frac{22}{  - 11} \\ h(-3) = -2

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3 years ago
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