Answer: Box3 has 120 oranges.
Box1 has 150 oranges.
Box has 130 oranges.
Step-by-step explanation:
I will answer this in English.
The question says:
3 boxes have 400 oranges.
The first one has 20 more than the second and 30 more than the third.
So we have 3 equations:
box1 + box2 + box3 = 400
box1 = box2 + 20
box1 = box3 + 30
Now, we can take the variable box1 in the third equation and replace it on the other two.
box3 + 30 + box2 + box3 = 400
box3 + 30 = box2 + 20
Now we can isolate one of the variables in the second equation, let's isolate box2.
box2 = box3 + 30 - 20 = box3 + 10
now we can replace it in the other equation:
box3 + 30 + box2 + box3 = 400
box3 + 30 + box3 + 10 + box3 = 400
3*box3 + 40 = 400
3*box3 = 400 - 40 = 360
box3 = 360/3 = 120.
Box3 has 120 oranges.
Box1 has 120 + 30 = 150 oranges.
Box has 150 - 20 = 130 oranges.
Answer:
The camera had to cover the greatest angle is CAMERA 3 because it had the largest angle of 71.47°
Step-by-step explanation:
From the above question,
We have:
Camera 1 = Angle A
Camera 2= Angle B
Camera 3 = Angle C
A = 210ft
B = 234ft
C = 260ft
We need to find Angle A( angle of camera 1) using the cosine rule
A=(B² + C² - 2BCCosA)
210² = 234² + 260² - 2 × 234 × 260 × CosA
210² = 122356 - 121680CosA
Square both sides
210² = 122356 - 121680CosA
44100 = 122356 - 121680CosA
121680CosA = 122356 - 44100
121680CosA = 78256
Cos A = 78256/121680
Cos A = 0.6431295201
A = arc cos (0.6431295201)
A = 49.974422249°
Angle A approximately = 49.97°
Using the Sine rule to find the Angle B
A/Sine A = B/Sine B
210ft/Sine 49.97° = 234ft/Sine B
210ft × Sine B = 49.97° × 234ft
Sine B =( Sine 49.97° × 234ft)/210ft
B = arc sin (0.8532172354)
Angle B = 58.56334
Approximately = 58.56°
Angle C = 180 - (49.97 + 58.56)°
Angle C = 71.47°
Therefore, the camera had to cover the greatest angle is Camera 3 because it had the largest angle of 71.47°
I think the answer is 2 because the unit price = price/total amount or weight
Price = 0.75 or 75 cents
Total Amount or weight = 5.25 pounds
Hope this helped☺☺
