All categories

2 years ago

Can anyone help on number 6?

Mathematics

1 answer:

mestny [16]2 years ago

4 0

Susana swam the fastest

You might be interested in

Find the total weekly earnings for a waitress with a weekly salary of $275 plus a 5% commission on dibners,if totalnworth of the

Citrus2011 [14]

The weekly earning for the waitress is $475.

Step-by-step explanation:

Weekly salary = $275

Commission = 5%

Worth of dinners served = $4000.00

Amount of commission = 5% of worth of dinners served

$Amount\ of\ commission=\frac{5}{100}*4000.00\\Amount\ of\ commission=0.05*4000.00\\Amount\ of\ commission=\$200$

Total earned = Weekly salary + Amount of commission

Total earned = $275+200=\$475$

The weekly earning for the waitress is $475.

Keywords: percentage, commission

Learn more about percentages at:

#LearnwithBrainly

7 0

3 years ago

Which value for the variable w makes the value of this expression 10?

Sidana [21]

Answer:

Step-by-step explanation:

50/5=10

therefore 5 is your answer

3 0

2 years ago

Read 2 more answers

Write this expression using numbers and symbols two less then six times a number

erma4kov [3.2K]

Answer:

Step-by-step explanation:

becaus ei did

8 0

2 years ago

What is the value of f(x)=2•2^x for f(-2)

Zigmanuir [339]

Answer:

The value of f(-2) is 1/2 or it can be written as 0.5.

Step-by-step explanation:

The given function is

$f(x)=2\cdot 2^x$

We have to find the value of f(-2).

Substitute x=-2 in the given function to find the value of f(-2).

$f(-2)=2\cdot 2^(-2)$

$f(-2)=2\cdot \frac{1}{2^(2)}$

$f(-2)=\frac{1}{2}$

$f(-2)=0.5$

Therefore the value of f(-2) is 1/2 or it can be written as 0.5.

3 0

3 years ago

WILL GIVE BRAINLIEST& 15 PTS.

kicyunya [14]

Answer:

The given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

Step-by-step explanation:

Consider the given fraction $\frac{x^3-x^2}{x^3}$

We have to reduce the fraction to the lowest terms.

Consider numerator $x^3-x^2$

We can take x² common from both the term,

Thus, numerator can be written as $x^2(x-1)$

Given expression can be rewritten as ,

$\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}$

We can now cancel $x^2$ from both numerator and denominator,

$\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}$

$\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}$

Thus, the given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

6 0

2 years ago

Read 2 more answers