Question

given that the center of a circle is at point (-3,5) and that the radius of the circle is 6 units, write the the equation of the circle

Answer 1

The equation of a cricle is 
$(x-h)^{2}+(y-k)^{2}=r^{2}$
h being the x coordinate of the given point and k being the y coordinate of the given point (r also being the radius). 

Now we have to plug the points into the equation 
$(x--3)^{2} +(y-5)^{2} = 6^{2}$
now just simplify the the equation
$(x+3)^{2} +(y-5)^{2} = 36$