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olasank [31]
3 years ago
15

What is the graph of the solution

Mathematics
1 answer:
Natalka [10]3 years ago
6 0

Answer:

Step-by-step explanation:

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In a random sample of 380 cars driven at low altitudes, 42 of them exceeded a standard of 10 grams of particulate pollution per
alexdok [17]

Answer:

The test statistic for testing if the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard is 3.234.

Step-by-step explanation:

We are given that in a random sample of 380 cars driven at low altitudes, 42 of them exceeded a standard of 10 grams of particulate pollution per gallon of fuel consumed.

In an independent random sample of 90 cars driven at high altitudes, 24 of them exceeded the standard.

Let p_1 = <u><em>population proportion of cars driven at high altitudes who exceeded a standard of 10 grams</em></u>.

p_2 = <u><em>population proportion of cars driven at low altitudes who exceeded a standard of 10 grams</em></u>.

So, Null Hypothesis, H_0 : p_1\leq p_2      {means that the proportion of high-altitude vehicles exceeding the standard is smaller than or equal to the proportion of low-altitude vehicles exceeding the standard}

Alternate Hypothesis, H_A : p_1>p_2      {means that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard}

The test statistics that will be used here is <u>Two-sample z-test statistics</u> for proportions;

                             T.S.  =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~  N(0,1)

where, \hat p_1 = sample proportion of cars driven at high altitudes who exceeded a standard of 10 grams = \frac{24}{90} = 0.27

\hat p_2 = sample proportion of cars driven at low altitudes who exceeded a standard of 10 grams = \frac{42}{380} = 0.11

n_1 = sample of cars driven at high altitudes = 90

n_2 = sample of cars driven at low altitudes = 380

So, the test statistics =  \frac{(0.27-0.11)-(0)}{\sqrt{\frac{0.27(1-0.27)}{90}+\frac{0.11(1-0.11)}{380} } }      

                                   =  3.234

The value of z-test statistics is 3.234.

7 0
3 years ago
Anyone wanna help? plss
ValentinkaMS [17]

Answer:

y= -5x + 4

m = -5x

y- int = 4.00

Step-by-step explanation:

subtract 5x from both sides.

6 0
2 years ago
Read 2 more answers
Describe the topics in this unit in your own words by explaining FIVE of the vocabulary words/phrases below. You will receive tw
daser333 [38]

Answer:

I'm sorry but I don't see any vocabulary words.

Step-by-step explanation:

4 0
3 years ago
Someone please help??
Deffense [45]

Answer:

  see below

Step-by-step explanation:

The problem statement seems to presume you have seen an exponential function like this written as ...

  f(t) = a0·(1 +r)^t

where a0 is the value corresponding to f(0) and "r" is the fractional rate at which the value increases for each increment of t.

Here, 1+r corresponds to 1.04 in the given function, so r = 0.04 = 4%. When the value is <em>greater than 0</em>, it means there is an <em>increase</em> by that fraction each time t increases by 1.

Here, t is not defined, either, but it would usually be used to represent years in a situation like this. (In other situations, it might represent months, hours, or millenia.)

Hence, the appropriate choice is the one that describes a 4% annual increase.

5 0
3 years ago
Please help me do to night
Vesna [10]

Answer:

1.) -4x+30y 2.) distributive property 3.) -4x+30y, (-0.4(3)+3(2)), 10(-1,2)+10(6), -12+60, =48

Step-by-step explanation:

10(-0.4x+3y)= 10(-0.4x)+10(3y)= -4x+30y

10(-0.4(3)+3(2))

10(-0.4(3))+10(3(2))

10(-1.2)+10(6)

-12+60

= 48

7 0
2 years ago
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