A discontinuity is a point that cannot exist because the x-coordinate would cause a problem in the equation. If you have a polynomial in the denominator, you must find which values of x would cause the polynomial in the denominator to evaluate to zero. Since division by zero is undefined, that would cause a discontinuity.
Let's look at your function.


is in the numerator. It is defined for every value of x. There is no problem there.

is in the denominator. This is a function defined for every value of x, but since it is in the denominator, we must exclude the x-value that would cause this polynomial to evaluate to zero.
We set it equal to zero and solve the equation for x.



For x = 0, the denominator has a value of zero, so at this point there is a discontinuity in function f(x).
The answer is:
B True because both graphs approaches x=0 but never touches it
E True if you just graph it out you can see that graph of g is going down and the graph of x is going up
A false because neither of the equations have a y intercept they have asymptote of x=0
C false because it is also a reflection across the x axis
D incorrect is because they both have domain {0<x<♾}
Hope this helped!
Answer:
B=-2+5 collecting like terms
B=3 answer
Simplifying
8x + -10 = 62
Reorder the terms:
-10 + 8x = 62
Solving
-10 + 8x = 62
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '10' to each side of the equation.
-10 + 10 + 8x = 62 + 10
Combine like terms: -10 + 10 = 0
0 + 8x = 62 + 10
8x = 62 + 10
Combine like terms: 62 + 10 = 72
8x = 72
Divide each side by '8'.
x = 9
Simplifying
x = 9
top four are yes yes no yes