How do you simplify 2(3p-4)+5

2 answers:

6 0

Solution

1) Expand
6p−8+5

2) Simplify
6p−3

ANSWER = 6p−3

Butoxors [25]3 years ago

6 0

You would multiply inside the parentheses first getting 6p-8+5 -8 + 5 is equal to -3 So therefor your simplist form would be 6p - 3 ? Idk this is what I thing

You might be interested in

Which of the following is another way to express the equation 8 - (-d) = 43?

Alecsey [184]

8 - (-d) = 43
8 + d = 43 <==

7 0

3 years ago

Mia has

Serggg [28]

Answer:

2 7/8

Step-by-step explanation:

first step is making these into improper fractions for example 6 1/8 would equal 49/8 because 6*8=48 and add the 1/8 to get 49/8 then do the same with the 3 1/4 make them into 8ths. so it would be 3 2/8 then 26/8 now subtract 49-26 to get 23/8. now simplify to get 2 7/8

5 0

2 years ago

Read 2 more answers

What is the inverse of y=2x+7

Katyanochek1 [597]

Y=(0,7)
Root: (-7/2,0)

3 0

3 years ago

Which of the following is a radical equation???

MaRussiya [10]

Maybe D ??

Step by step explanation

4 0

3 years ago

1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch

kykrilka [37]

Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.

Thus, half the angle formed by the chord at the centre of the circle is given by:

$\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2} \\ \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o$

Now,

$\sin60^o= \frac{9}{r} \\ \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392$

Therefore, the radius of the circle is 10.4 cm to 1 d.p.

Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

$\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o$

Now,

$\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm$

Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

$\sin40^o= \frac{y}{10} \\ \\ \\ \Rightarrow y=10\sin40^o=6.428$

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.

3 0

3 years ago